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Ira Lisetskai [31]
3 years ago
6

The concentration of KBr in a solution prepared by dissolving 2.21g of KBr in 897 g of water is __________ m.

Chemistry
1 answer:
anyanavicka [17]3 years ago
4 0

Answer:

E) 0.0207

Explanation:

The molal concentration, m, is defined as the ratio between moles of solute (In this case, KBr) per kg of solvent (water):

<em>Moles KBr -Molar mass: 119g/mol-</em>

2.21g KBr * (1mol / 119g) = 0.01857moles

<em>Mass solvent:</em>

897g * (1kg / 1000g) = 0.897kg

Molal concentration:

0.01857 moles / 0.897kg =

0.0207m

Right solution is:

<h3>E) 0.0207. </h3>

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