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Sergio [31]
3 years ago
11

A bicycle racer rides from a starting marker to a turnaround marker at 10 m/s. She then rides back along the same route from the

turnaround marker to the starting marker at 25 m/s. What is her average speed for the whole race?
Physics
1 answer:
andrew11 [14]3 years ago
3 0

Given :

A bicycle racer rides from a starting marker to a turnaround marker at 10 m/s.

She then rides back along the same route from the turnaround marker to the starting marker at 25 m/s.

To Find :

Her average speed for the whole race.

Solution :

We know, average velocity is given by :

Average \ Velocity = \dfrac{v_1 + v_2}{2}\\\\Average\ Velocity = \dfrac{10 + 25}{2}\\\\Average \ Velocity = \dfrac{35}{2}\\\\Average \ Velocity = 17.5 \ m/s

Therefore, average speed for the whole race is given by 17.5 m/s.

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Newtons first law 1 to 5. <br>What is each of the net force for all of the 5 questions? ​
erica [24]

Answer:

1. 65 N.

2. 160 N.

3. 0 N.

4. 210 N.

5. 90 N.

Explanation:

1. Determination of the net force.

Force applied to the right (Fᵣ) = 80 N

Force applied to the left (Fₗ) = 145 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 145 – 80

Fₙ = 65 N

Thus, the net force is 65 N

2. Determination of the net force.

Force 1 applied to the left (F₁) = 35 N

Force 2 applied to the left (F₂) = 125 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 35 + 125

Fₙ = 160 N

Thus, the net force is 160 N.

3. Determination of the net force.

Force applied to the right (Fᵣ) = 75 N

Force applied to the left (Fₗ) = 75 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 75 – 75

Fₙ = 0

Thus, the net force is 0 N

4. Determination of the net force.

Force 1 applied to the right (F₁) = 150 N

Force 2 applied to the right (F₂) = 60 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 150 + 60

Fₙ = 210 N

Thus, the net force is 210 N.

5. Determination of the net force.

Force applied to the right (Fᵣ) = 115 N

Force applied to the left (Fₗ) = 25 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 115 – 25

Fₙ = 90 N

Thus, the net force is 90 N

8 0
3 years ago
An object with a mass of 6.0 kg accelerates 8.0 m/s^2 when an unknown force is applied to it. What is the amount of the force? R
iren [92.7K]

Answer:

48N

Explanation:

use F=ma, or force is equal to mass multiplied by acceleration.

8 0
3 years ago
Answer these multiple choice questions!!! 20 points!!!
irga5000 [103]
I need pictures or something
7 0
3 years ago
Read 2 more answers
.
beks73 [17]

Answer:

2 m/s²

Explanation:

the equations of motion are

S= ut +½at²

v² = u²+ 2as

v = u + at

s = (u+v)/2 × t

From the parameters given

u = 0m/s this is because it starts from rest

Distance (s)  = 9m

Time (t)  = 3s

Based on this the first equation would be used

s = ut + ½at²

Input values

9 = 0×3 + ½ × a x 3²

9 = 0 + 9a/2

9 = 4.5a

Divide both sides by 4.5

a = 9 / 4.5 m/s²

a = 2 m/s²

I hope this was helpful, please mark as brainliest

3 0
4 years ago
An eagle flew for 3 hours at 115 km/h and 5 hours at 136 km/h. How far did the eagle fly?
Yanka [14]

Answer:

the eagle flew 1,025 km

Explanation:

since the eagle flew for 3 hours at 115 km/h it flew a total of 345 km during that time. During the 5 hours at 136 km/h the eagle flew a total of 680 km.

3 0
3 years ago
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