Answer:
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Answer:
COP_max = 18.69
Explanation:
We are given;
Heated space temperature; T_H = 26°C = 273K + 26 = 299K
Temperature at which heat is extracted; T_L = 10°C = 273 + 10 = 283K
Now the Coefficient of performance (COP) of a heat pump will be a maximum when the heat pump operates in a reversible manner. The COP of a reversible heat pump depends on the temperature limits in the cycle only and is determined by the formula;
COP_max = 1/(1 - (T_L/T_H))
Thus,
COP_max = 1/(1 - (283/299))
COP_max = 1/(1 - 0.9465)
COP_max = 1/0.0535 = 18.69
Answer:
In the passage, it has been mentioned that the president of CFR received the letter from GET, who offered them to install the network servers at the cost of $5 million and the president of CFR also accept it. Although the GET will charge 50 percent more charges after getting the news of heavy tax on technology providers, I will not accept it. As a president of CFR my argument will be that I will ask them (GET) to install the servers at the earlier price that the GET offers before heavy taxation, otherwise, I will reject the offer as I had not formally agreed. Because, the president already informed them about the acceptance of the offer.
My other argument will be that if the GET will not accept my previous proposal, I will go to another technology provider, who can offer the service at a lower cost in comparison to the GET.
Answer:
a) -505.229 kJ/Kg
b) -1.724 kJ/kg
Explanation:
T1 = 400°C
P1 = 3 MPa
P2 = 125 kPa
work output = 530 kJ/kg
surrounding temperature = 20°C = 293 k
<u>A) Calculate heat transfer from Turbine to surroundings </u>
Q = h2 + w - h1
h ( enthalpy )
h1 = 3231.229 kj/kg
enthalpy at P2
h2 = hg = 2676 kj/kg
back to equation 1
Q = 2676 + 50 - 3231.229 = -505.229 kJ/Kg ( i.e. heat is lost )
<u>b) Entropy generation </u>
entropy generation = Δs ( surrounding ) + Δs(system)
= - 505.229 / 293 + 0
= -1.724 kJ/kg
