Question

Which of the following combinations of quantum numbers is permissible?Question 23 options: n = 1, l = 2, ml = 0, ms = n = 4, l = 3, ml = 1, ms = n = 3, l = 3, ml = 1, ms = n = 2, l = 1, ml = –1, ms = 0 n = 4, l = 3, ml = 4, ms =

Answer 1

Answer: n= 4, , l= 3, $m_l$ = 1,  permissible

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1).For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as $m_l$. The value of this quantum number ranges from $(-l\text{ to }+l).$

Spin Quantum number : It describes the direction of electron spin. This is represented as $m_s$. The value of this is $+\frac{1}{2}$ for upward spin and $-\frac{1}{2}$ for downward spin.

a) n=1 , l= 2, $m_l$ = 0,  not permissible as l can not greater than n.

b) n= 4, , l= 3, $m_l$ = 1,  permissible

c) n= 3, l= 3, $m_l$ = 1, not permissible as l can not equal than n.

d) n= 4 , l= 3, $m_l$ = 4,  not permissible as $m_l$ can not greater than l.