Torque = r x F
|F| = mg = 60 * 10 N = 600 N ( assuming g ~ 10m/s^2)
distance of fulcrum = torque / Force = 90/600 m = .15 m.
Answer:
The horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
Explanation:
Given;
height above the ground, h = 16.4 m
speed of the eagle, v = 9.3 m/s
The time it will take the pumpkin to fall at the given height is calculated as;
The horizontal distance traveled at this time is given by;
x = vt
x = (9.3)(1.83)
x = 17.02 m
Therefore, the horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
<h2>
It takes 0.867 seconds to get to the top of its motion</h2>
Explanation:
We have equation of motion v = u + at
Initial velocity, u = 8.5 m/s
Final velocity, v = 0 m/s - At maximum height
Time, t = ?
Acceleration , a = -9.81 m/s²
Substituting
v = u + at
0 = 8.5 + -9.81 x t
t = 0.867 s
It takes 0.867 seconds to get to the top of its motion
19.6 N........weight is equal to mass multiplied by gravitational force which is 9.8 m/s2......2 x 9.8 gives 19.6 N
Answer:
<h2>1960 J</h2>
Explanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
PE = 10 × 9.8 × 20
We have the final answer as
<h3>1960 J</h3>
Hope this helps you
