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s344n2d4d5 [400]
3 years ago
7

Steve has a mass of 78 kg and is standing still on very slippery ice while holding a 2.5 kg can of peas. Steve throws the can to

the right so that it travels with a velocity of 8.7 m/s. What is Steve’s velocity after he throws the can?
Physics
1 answer:
anzhelika [568]3 years ago
5 0
Answer: 0.28 m/s


Let

M1 = mass of Steve
V1 = velocity of Steve
M2 = mass of can
V2 = velocity of can

Because momentum is a conserved quantity:

P1 - P2 = 0

So

M1*V1 - M2*V2 = 0

78.0kg(V1) - 2.5kg(8.7m/s) = 0

78.0(V1) = 21.75

V1= 0.28 m/s
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Since the speed of sound and light remains constant in a particular medium, we can use
      Speed = Distance/Time

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3 years ago
A runner starts from rest and in 3 s reaches a speed of 8 m/s. If we assume that the speed changed at a constant rate (constant
Stells [14]

Answer:

The average speed of the runner is 4 m/s.

Explanation:

Hi there!

The average speed (a.s) is calculated by dividing the traveled distance (d) over the time needed to travel that distance (t):

a.s = d / t

So, let´s find the distance traveled in those 3 s. For that, we can use the equation of position of an object moving in a straight line with constant acceleration:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

If we place the origin of the frame of reference at the point where the runner starts, then, x0 = 0. Since the runner starts from rest, v0 = 0. So, the equation gets reduced to this:

x = 1/2 · a · t²

We have the time (3 s), so let´s find the acceleration. For that, we can use the equation of velocity of an object moving in a straight line with constant acceleration:

v = v0 + a · t

Where "v" is the velocity at a time "t". Since v0 = 0, then:

v = a · t

At t = 3 s, v = 8 m/s

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So let´s find the position of the runner at t = 3 s (In this case, the position of the runner will be equal to the traveled distance):

x = 1/2 · a · t²

x = 1/2 · 8/3 m/s² · (3 s)²

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Now, we can calcualte the average speed:

a.s = d/t

a.s = 12 m / 3 s

a.s = 4 m/s

The average speed of the runner is 4 m/s.

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Given

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