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2 years ago

A car is traveling west for 12 s its speed is 36.12 m/s in the same direction find the total distance the car traveled

Physics

1 answer:

ki77a [65]2 years ago

4 0

<u>We are given:</u>

constant speed of the car (u) = 36.12 m/s

time in question (t) = 12 seconds

<u>Solving for the Distance and Displacement:</u>

from the second equation of motion:

s = ut + 1/2 at^2

since we have 0 acceleration:

s = ut

<em>replacing the variables</em>

s = 36.12 * 12

s = 433.44 m

Since the car is travelling in a straight line towards the same direction, it's Distance will be equal to its Displacement

Hence, both the Displacement and <u>Distance covered by the car is </u>

but since Displacement also has a direction vector along with it,

the <u>Displacement will be 433.44 m due west</u>

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PSYCHO15rus [73]

The car is accelerating at 3 m/s² in the positive direction (to the right). By Newton's second law, the net force on the car in this direction is

∑ F = F[a] - F[f] - F[air] = ma

3100 N - 200 N - F[air] = (650 kg) (3 m/s²)

Solve for F[air] :

F[air] = 3100 N - 200 N - (650 kg) (3 m/s²)

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2 years ago

a 25-N net force is applied to a rolling cart and pruduces an acceleration of 5 m/s 2 what’s the cart mass

nignag [31]

Answer:

The mass of the cart is 5 kg

Explanation:

You divide 25 by 5 and get 5. Have a great day! :D

<em>The Equation:</em>

25/5 = 5

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2 years ago

Two students, Student X and Student Y, stand on a long skateboard that is at rest on a flat, horizontal surface, as shown. In or

OleMash [197]

Answer:

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Explanation:

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4 years ago

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Consider two objects (Object 1 and Object 2) moving in the same direction on a frictionless surface. Object 1 moves with speed v

d1i1m1o1n [39]

1) A) Object 1 has the greater momentum

The magnitude of the momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is its speed

Object 1 has a mass of $m_1 = 2m$ and a speed of $v_1 = v$ , so its momentum is

$p_1 = m_1 v_1 = (2m)(v)=2mv$

Object 2 has a mass of $m_2 = m$ and a speed of $v_2 = \sqrt{2} v$ , so its momentum is

$p_2 = m_2 v_2 = (m)(\sqrt{2} v)=\sqrt{2}mv$

So we see that $p_1 > p_2$ , so object 1 has the greater momentum.

2) The objects have the same kinetic energy.

The kinetic energy of an object is given by

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

Object 1 has a mass of $m_1 = 2m$ and a speed of $v_1 = v$ , so its kinetic energy is

$K_1 = \frac{1}{2}m_1 v_1^2 = \frac{1}{2}(2m)(v)^2=mv^2$

Object 2 has a mass of $m_2 = m$ and a speed of $v_2 = \sqrt{2} v$ , so its kinetic energy is

$K_2 = \frac{1}{2}m_2 v_2^2 = \frac{1}{2}(m)(\sqrt{2} v)^2=mv^2$

So we see that $K_1 =K_2$ , so the objects have same kinetic energy

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3 years ago

How long will it take a 400 W engine to lift a 100 N object up to a height of 80 m?

Norma-Jean [14]

<h3>Answer:</h3>

20 seconds

<h3>Explanation:</h3>

<u>We are given</u>;

Power of the engine as 400 watts
Force as 100 N
Distance the object is lifted up as 80 m

We are required to determine the time taken.

We need to know that power is the rate of work done

Therefore;

Power = Work done ÷ time

But, work done = Force × distance

Therefore; In this case;

Work done = 100 N × 80 m

= 8000 Joules

Since , Power = Work done ÷ time

Then, time = Work done ÷ Power

Thus;

Time = 8000 J ÷ 400 W

= 20 s

Therefore, the time taken by the engine to lift the object is 20 seconds

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4 years ago

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