<u>We are given:</u>
constant speed of the car (u) = 36.12 m/s
time in question (t) = 12 seconds
<u>Solving for the Distance and Displacement:</u>
from the second equation of motion:
s = ut + 1/2 at^2
since we have 0 acceleration:
s = ut
<em>replacing the variables</em>
s = 36.12 * 12
s = 433.44 m
Since the car is travelling in a straight line towards the same direction, it's Distance will be equal to its Displacement
Hence, both the Displacement and <u>Distance covered by the car is </u>
<u>433.44 m</u>
but since Displacement also has a direction vector along with it,
the <u>Displacement will be 433.44 m due west</u>