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3 years ago

What is the weight of an astronaut with a mass of 75 kg on the moon? The gravitational field strength on the moon is 1.6 Nkg-1.

Physics

1 answer:

bearhunter [10]3 years ago

7 0

okay this is kinda easy

<u>What is the gravitational field strength on the moon?</u>

The Moon has a gravitational field strength of 1.6 N/kg.

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Shine the flashlight on the liquid crystal sheet. Did you observe evidence that light carries energy?

Artemon [7]

Answer:

no i did not observe anything

Explanation:

6 0

3 years ago

The motors that drive airplane propellers are, in some cases, tuned by using beats. The whirring motor produces a sound wave hav

sweet-ann [11.9K]

Answer:

A) 2 possible frequencies of second propellar = 424 rpm or 724 rpm

B) Correct frequency is f2 = 724 rpm

C) Reason is stated in explanation

Explanation:

A) We are given;

Frequency of first propeller; f1 = 574 rpm

Beat frequency; f_beat = 2.5 Hz = 2.5 × 60 rpm = 150 rpm

Now, formula for the beat frequency is;

f_beat = |f1 - f2|

Now, |f1 - f2| means it is inside an absolute value.

Thus, it means,

f1 - f2 = 150 or f2 - f1 = 150

Thus;

574 - f2 = 150

Or f2 - 574 = 150

So,f2 = 574 - 150 = 424 rpm or f2 = 574 + 150 = 724 rpm

2 possible frequencies of second propellar = 424 rpm or 724 rpm

B) Now, if we increase the speed of the second propellar slightly, it means that f2 will increase as well.

Now, from the 2 possible values of f2 gotten, we can see that for f1 - f2 = 150, when we increase f2, the beat frequency will reduce while for f2 - f1 = 150, when we increase f2, the beat frequency will increase.

Thus, it's the frequency of f2 gotten in f2 - f1 = 150 that is the correct answer.

Thus, when we increase the speed of the second propellar slightly, it means that;

f2 = 724 rpm

C) Answer in part B is correct because as we increase the speed of the second propellar, the frequency will also increase and the value of f2 that corresponds with an increase in speed is 724 rpm.

7 0

3 years ago

Jake drags a sled of mass 25 kg across the snow. The sled is attached to a rope that pulls with a force of 50 N at an angle of 3

madam [21]

Answer:

218.5 N

Explanation:

In order for the sled to be in equilibrium along the vertical direction, the forces acting along this direction must be balanced. So the equilibrium equation is:

$N+F sin \theta - mg =0$

where

N is the normal force

F = 50 N is the force that pulls the sled

$\theta$ is the angle between the force and the horizontal, so

$F sin \theta$ is the component of F acting along the vertical direction

(mg) is the weight of the sled, with

m = 25 kg being the mass of the sled

g = 9.8 m/s^2 is the acceleration due to gravity

Solving the formula for N, we find

$N=mg-F sin \theta = (25 kg)(9.8 m/s^2)-(50 N)sin 32^{\circ}=218.5 N$

7 0

3 years ago

A solid sphere of radius R is made of an insulating material. It holds a charge, Q, which is distributed evenly throughout the s

Vinvika [58]

Answer:

The magnitude of Electric Field is $E=\dfrac{Qr}{4\pi \epsilon_0 R^3}$

Explanation:

Given:

Radius of the solid sphere=R
Total charge of the sphere=Q

Let consider a Gaussian surface at a distance of r such that 0<r>R in the shape of sphere such that the electric Field due to this E and it is radially outwards.

The charge inside this Gaussian surface volume we have , $q_{in}=\dfrac{Qr^3}{R^3}$

Now using Gauss Law we have

$E\times4\pi r^2=\dfrac{q_{in}}{\epsilon_0}\\E\times4\pi r^2=\dfrac{\dfrac{Qr^3}{R^3}}{\epsilon_0}\\E=\dfrac{Qr}{4\pi \epsilon_0 R^3}$

5 0

3 years ago

What type of electromagnetic wave does a cloud fall under?

slava [35]

The answer is a cloud

3 0

3 years ago