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Marina86 [1]
3 years ago
10

When do things move faster in traffic? Day or night? and why?​

Engineering
2 answers:
sweet-ann [11.9K]3 years ago
8 0

Answer:

In night they do because it is closer to rush hour but more like the evening

Explanation:

antoniya [11.8K]3 years ago
3 0

Answer:

Night

Explanation: things love faster in traffic at night because there are less cars on the road and less people are commuting from place to place.

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function summedValue = SummationWithLoop(userNum) % Summation of all values from 1 to userNum summedValue = 0; i = 1; % Write a
Alexeev081 [22]

Answer:

function summedValue = SummationWithLoop(userNum)

% Summation of all values from 1 to userNum

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  i = 0;

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8 0
3 years ago
At time t the resultant force on a particle, of mass 250kg is (300ti-400tj)N. Initially, the particle is at the origin and is mo
Harlamova29_29 [7]

Answer:

i

Explanation:

4 0
2 years ago
Javier’s class visited a power plant near his city, and they learned how it produced electricity. What does this form of power d
adelina 88 [10]

The electricity is generated by the burning of fuel in the power plant that increases the kinetic energy of water vapor which rotates the turbine and shaft of the generator.

<h3>What is a power plant?</h3>

A power plant is a place where heavy machinery objects are installed to produce electricity.

The power is generated in the power plant with the help of the burning of fuel that increases the temperature of the boiler. There are so many tubes in which water is present. Water absorbs heat and increases its kinetic energy. And this kinetic energy help to rotate the turbine and the shaft of the generator is attached to the turbine as result electricity is generated.

More about the power plant link is given below.

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5 0
2 years ago
A train consists of a 50 Mg engine and three cars, each having a mass of 30 Mg . If it takes 75 s for the train to increase its
ohaa [14]

Answer:

T = 15 kN

F = 23.33 kN

Explanation:

Given the data in the question,

We apply the impulse momentum principle on the total system,

mv₁ + ∑\int\limits^{t2}_{t1} {Fx} \, dt = mv₂

we substitute

[50 + 3(30)]×10³ × 0 + FΔt = [50 + 3(30)]×10³ ×  ( 45 × 1000 / 3600 )  

F( 75 - 0 ) =  1.75 × 10⁶

The resultant frictional tractive force F is will then be;

F =  1.75 × 10⁶ / 75

F = 23333.33 N

F = 23.33 kN

Applying the impulse momentum principle on the three cars;

mv₁ + ∑\int\limits^{t2}_{t1} {Fx} \, dt = mv₂

[3(30)]×10³ × 0 + FΔt = [3(30)]×10³ ×  ( 45 × 1000 / 3600 )  

F(75-0) = 1.125 × 10⁶

The force T developed is then;

T =  1.125 × 10⁶ / 75

T = 15000 N

T = 15 kN

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2 years ago
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