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3 years ago

6

The purpose of a nuclear power plant is to transform nuclear energy to electricity. this is done in steps starting with a nuclea

r reaction which generates heat to produce steam. the steam in turn is used to turn a generator which finally produces electricity. which answer best illustrates these energy transformation.
A. nuclear --> mechanical --> chemical --> electrical
B. thermal --> nuclear --> mechanical --> electrical
C. mechanical --> thermal --> nuclear ->electrical
D. nuclear --> thermal --> mechanical --> electrical

2 answers:

kodGreya [7K]3 years ago

7 0

Answer:

Nuclear --> Thermal --> Mechanical --> Electrical

Hope this is useful!! :))

lina2011 [118]3 years ago

7 0

It's D, nuclear to thermal to mechanical to electrical

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A fluid is flowing through a circulat tube at 0.4 kg/s. Tube inner surface is smooth with a diameter 0.014 m. Fluid density is 9

ElenaW [278]

Answer:

The convection coefficient is $15456.48\ W/m^{2}K$

Solution:

Mass flow rate, $\dot{m} = 0.4\ kg$

Inner diameter of the tube, d = 0.014 m

Fluid density, $\rho_{f} = 990\ kg/m^{3}$

Specific Heat, C = 3845 J/K

Thermal Conductivity, K = 0.74

Prandtl Number, $P_{r} = 8.6$

Heat flux, $\dot{q} = 71,297\ W/m^{2}$

Viscosity, $\mu = 0.00079\ Ns/m^{2}$

Now,

To calculate the convection heat coefficient, h:

Determine the cross sectional area of the circular tube:

$A_{c} = \frac{\pi}{4}d^{2} = \frac{\pi}{4}\times (0.014)^{2} = 1.54\time 10^{- 4}\ m^{2}$

Determine the velocity of the fluid inside the tube by mass flow rate:

$\dot{m} = \rho_{f}A_{c}v$

$0.4 = 990\times 1.54\time 10^{- 4}v$

v = 2.624 m/s

Determine the Reynold's Number, $R_{e}$ :

$R_{e} = \frac{\rho_{f}dv}{\mu}$

$R_{e} = \frac{990\times 0.014\times 2.624}{0.00079} = 46036.253$

Thus it is clear that $R_{e}$ > 10,000 hence flow is turbulent.

Now,

Determine the Nusselt Number:

$N_{u} = 0.023R_{e}^{0.8}P_{r}^{0.4}$

$N_{u} = 0.023\times 46036.253^{0.8}\times 8.6^{0.4} = 292.42$

Also,

$N_{u} = \frac{dh}{K}$

where

h = convection coefficient

Now,

$292.42 = \frac{0.014\times h}{0.74}$

$h = 15456.48\ W/m^{2}K$

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4 years ago

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viva [34]

Well, I'll try to write the formula in a way that's not confusing,
but I'm afraid it might be slightly confusing anyway.

When you're working with dB, the basic rule is

   A change of 10 dB means either multiplying or dividing by 10 .

   Multiply something by 10 ==> it increases by 10 dB.
   Divide something by 10 ==> it decreases by 10 dB.

It turns out that another way to write all of this is . . .

   An increase of 10 dB ===> multiply the original amount by 10¹
   An increase of 20 dB ===> multiply the original amount by 10²
   An increase of, say, 7 dB ===> multiply the original amount by 10⁰·⁷

   A decrease of 10 dB ===> multiply the original amount by 10⁻¹
   A decrease of 30 dB ===> multiply the original amount by 10⁻³
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This question says: The sound increases by 5 dB .

That means the original 'intensity' or 'power' of the sound
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From the choices listed, the closest one is (c).

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4 years ago

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vladimir1956 [14]

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Explanation:

Given

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$i=i_0\left [ 1-e^{-\frac{t}{\tau }}\right ]$

where $i_0$ is maximum current

i=current at any time

$\tau =\frac{L}{R}=time\ constant$

$\tau '=\frac{2L}{R}=2\tau$

thus if inductance is doubled then time constant also gets doubled or twice to its original value.

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