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Luba_88 [7]
3 years ago
13

Pedro adds 3.23 moles of helium to a balloon that already contained 4.51 moles of helium creating a balloon with a volume of 9.8

7 liters. What was the volume of the balloon before the addition of the extra gas?
Chemistry
1 answer:
sashaice [31]3 years ago
5 0

Answer:

7.The answer is 2.13 because if u add 3.23 and 4.51 and the answer is 7.74 and u add 2.13 to get 9.87. 3.23 + 4.51 + 2.13 is 9.87

Explanation:

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83ef0c8
kumpel [21]

Answer:

0.17325 moles per liter per second

Explanation:

For a first order reaction;

in[A] = in[A]o - kt

Where;

[A]= concentration at time t

[A]o = initial concentration

k= rate constant

t= time taken

ln0.5 =ln1 - 2k

2k = ln1 - ln0.5

k= ln1 - ln0.5/2

k= 0 -(0.693)/2

k= 0.693/2

k= 0.3465 s-1

Rate of reaction = k[A]

Rate = 0.3465 s-1 × 0.50 mol/L

Rate = 0.17325 moles per liter per second

5 0
3 years ago
An atom of boron has an atomic number of 5 and an atomic mass of 11. the atom contains
kirill [66]
The atom contain 6 neutrons, if that's the question
8 0
3 years ago
Objects that are able to fall have what type of energy?
ASHA 777 [7]

Answer:

kinetic energy

Explanation:

because of the movement of gravity and space

4 0
3 years ago
Which test tubes were used to determine the optimal ph for lipase activity?
d1i1m1o1n [39]
The tubes 1, 5 and 6 is the answer to the question which test tubes were used to determine the optimal ph lipase activity. Lipase is an enzyme and optimum ph the maximum possible point on which enzyme become active.
5 0
3 years ago
A 10.0 mL sample of HNO3 was exactly neutralized by 13.5 mL of 1.0 M KOH. What is the molarity of the HNO3? Use the titrations f
Kruka [31]

Answer: Thus molarity of HNO_3 is 1.35 M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=1.0M\\V_2=13.5mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 1.0\times 13.5\\\\M_1=1.35M

Thus molarity of HNO_3 is 1.35 M

7 0
3 years ago
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