Given a steel rod:
Radius = r = 10 mm = 0.010 m.
Length L = 1 m.
Tensile Force = F = 100 kN.
Young's Modulus = Y = 2.0 &* 10¹¹ Nm⁻²
a) Stress = Force/cross sectional area
σ = F / A
= 100,000 /(π 0.010²) Pa
= 318.309 MPa
b) Y = (F/A) / (ΔL/L)
Elongation ΔL = L F / (A Y)
= L σ / Y
= 1 * 318.309 * 10⁶ / 2.0 * 10¹¹ m
= 1.591 mm
c) Percentage elongation : ΔL/L * 100 = 0.1591 %
Answer:
The pair of terminals to produce an output voltage of 8V are K and M.
Explanation:
A transformer is an electronic device that can be used to increase or decrease an output voltage. It consists of secondary and primary coils, and operates on the principle of induction.
= ![\frac{N_{s} }{N_{p} }](https://tex.z-dn.net/?f=%5Cfrac%7BN_%7Bs%7D%20%7D%7BN_%7Bp%7D%20%7D)
where:
is the voltage in the secondary coil,
is the voltage in the primary coil,
is the number of turns in the secondary coil and
is the number of turns in the primary coil.
In the question, let us combine the number of turns in the secondary coil. So that,
= 15 + 5 = 20
= ![\frac{20}{500}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B500%7D)
= ![\frac{4000}{500}](https://tex.z-dn.net/?f=%5Cfrac%7B4000%7D%7B500%7D)
= 8
= 8V
For the output voltage to be equal to 8V, the pair of terminals required are K and M.
Answer:
The ratio is 0.667.
Explanation:
We are given two incandescent lights which have ratings of 75 W and 50 W .
Both bulbs operate at the same voltage.
The equation of power consumed is given by P = ![\frac{V^2}{R}](https://tex.z-dn.net/?f=%5Cfrac%7BV%5E2%7D%7BR%7D)
Therefore the resistance for the 75 W bulb = ![\frac{V^2}{75}](https://tex.z-dn.net/?f=%5Cfrac%7BV%5E2%7D%7B75%7D)
Therefore the resistance for the 50 W bulb = ![\frac{V^2}{50}](https://tex.z-dn.net/?f=%5Cfrac%7BV%5E2%7D%7B50%7D)
Therefore the ratio of the resistance for the 75 W bulb to the resistance of the 50 W bulb is equal to
=
=
= 0.667.
The ratio is 0.667.
Answer:
1600 N
Explanation:
pascals principle says..
![\frac{A_{out}}{A_{in}} = \frac{F_{out}}{F_{in}} \\](https://tex.z-dn.net/?f=%5Cfrac%7BA_%7Bout%7D%7D%7BA_%7Bin%7D%7D%20%3D%20%20%5Cfrac%7BF_%7Bout%7D%7D%7BF_%7Bin%7D%7D%20%5C%5C)
so lets do
![\frac{2}{4} = \frac{x}{3200}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B4%7D%20%3D%20%5Cfrac%7Bx%7D%7B3200%7D)
so multiply one half (2/4 simplified) by 3200
1600 is equal to x
1600 N
YAAAAAAAAAAAAAAY
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