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viva [34]
2 years ago
7

On Earth, a scale shows that you weigh 585 N. What would the scale read on the Moon (g = 1.60 m/s2)? N

Physics
1 answer:
Serggg [28]2 years ago
8 0

Answer:

95.51 N

Explanation:

First, find the mass in kg:

Fg = 585 N

Fg = m*g

585 N = m*9.8 m/s^2

<u>m = 59.69 kg</u>

Then, to find your weight (Fg) on the moon, you use the same equation of

Fg(moon) = m*g, except this time g = 1.60 m/s^2

Fg(moon) = 59.69 kg * 1.60 m/s^2

Fg(moon) = 95.51 N

Hope this helps!! :)

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People travel from all over the world to see more than 30 glaciers at Glacier National Park in Alaska.
Whitepunk [10]
The answer I believe is c
Explanation
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Explanation:

c. if the vector is oriented at 0° from the X -axis.

6 0
2 years ago
A moving particle encounters an external electric field that decreases its kinetic energy from 9520 eV to 7060 eV as the particl
Sati [7]

Given Information:

KEa = 9520 eV

KEb = 7060 eV

Electric potential = Va = -55 V

Electric potential = Vb = +27 V

Required Information:

Charge of the particle = q = ?

Answer:

Charge of the particle = +4.8x10⁻¹⁸ C

Explanation:

From the law of conservation of energy, we have

ΔKE = -qΔV

KEb - KEa = -q(Vb - Va)

-q = KEb - KEa/Vb - Va

-q = 7060 - 9520/27 - (-55)

-q = 7060 - 9520/27 + 55

-q = -2460/82

minus sign cancels out

q = 2460/82

Convert eV into Joules by multiplying it with 1.60x10⁻¹⁹

q = 2460(1.60x10⁻¹⁹)/82

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6 0
3 years ago
The suspension cable of a 1,000 kg elevator snaps, sending the elevator moving downward through its shaft. The emergency brakes
tester [92]

Answer:

option (E) 1,000,000 J

Explanation:

Given:

Mass of the suspension cable, m = 1,000 kg

Distance, h = 100 m

Now,

from the work energy theorem

Work done by the gravity = Work done by brake

or

mgh = Work done by brake

where, g is the acceleration due to the gravity = 10 m/s²

or

Work done by brake  = 1000 × 10 × 100

or

Work done by brake = 1,000,000 J

this work done is the release of heat in the brakes

Hence, the correct answer is option (E) 1,000,000 J

4 0
3 years ago
A ship's propeller of diameter 3 m makes 10.6 revolutions in 30s. What is the angular velocity of the propeller?
ycow [4]

Answer:

The angular velocity of the propeller is 2.22 rad/s.

Explanation:

The angular velocity (ω) of the propeller is:  

\omega = \frac{\Delta \theta}{\Delta t}                              

Where:

θ: is the angular displacement = 10.6 revolutions

t: is the time = 30 s

\omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s

Therefore, the angular velocity of the propeller is 2.22 rad/s.

I hope it helps you!

5 0
3 years ago
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