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3 years ago

Examine this diagram of the human heart. what is the structure indicated by the arrow?

Physics

2 answers:

natima [27]3 years ago

5 0

Answer:

A.) Pulmonary artery

Explanation: Someone told me Aorta and i got it wrong....

taurus [48]3 years ago

4 0

Answer:

Right coronary artery

Explanation:

Right coronary artery (RCA). The right coronary artery supplies blood to the right ventricle, the right atrium, and the SA (sinoatrial) and AV (atrioventricular) nodes, which regulate the heart rhythm.

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Calculate the solubility (in m units) of ammonia gas in water at 298 k and a partial pressure of 2.50 bar . the henry's law cons

Eduardwww [97]

Henry's Law (formulated in 1803 by William Henry) states that aa constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid.
Mathematically it can be formulated as
C = H⨯P
being:
C: the molar concentration of dissolved gas A,
P: the partial pressure of it
H: Henry's constant
Substituting:
C = P * H
C = (2.50 * 0.9869) * 58.0
C = 143.1
Answer:
the solubility (in m units) is
C = 143.1

8 0

3 years ago

8. An unpowered flywheel is slowed by a constant frictional torque. At time t = 0 it has an angular velocity of 200 rad/s. Ten s

allsm [11]

Answer:

a) $\omega = 50\,\frac{rad}{s}$ , b) $\omega = 0\,\frac{rad}{s}$

Explanation:

The magnitude of torque is a form of moment, that is, a product of force and lever arm (distance), and force is the product of mass and acceleration for rotating systems with constant mass. That is:

$\tau = F \cdot r$

$\tau = m\cdot a \cdot r$

$\tau = m \cdot \alpha \cdot r^{2}$

Where $\alpha$ is the angular acceleration, which is constant as torque is constant. Angular deceleration experimented by the unpowered flywheel is:

$\alpha = \frac{170\,\frac{rad}{s} - 200\,\frac{rad}{s} }{10\,s}$

$\alpha = -3\,\frac{rad}{s^{2}}$

Now, angular velocities of the unpowered flywheel at 50 seconds and 100 seconds are, respectively:

a) t = 50 s.

$\omega = 200\,\frac{rad}{s} - \left(3\,\frac{rad}{s^{2}} \right) \cdot (50\,s)$

$\omega = 50\,\frac{rad}{s}$

b) t = 100 s.

Given that friction is of reactive nature. Frictional torque works on the unpowered flywheel until angular velocity is reduced to zero, whose instant is:

$t = \frac{0\,\frac{rad}{s}-200\,\frac{rad}{s} }{\left(-3\,\frac{rad}{s^{2}} \right)}$

$t = 66.667\,s$

Since $t > 66.667\,s$ , then the angular velocity is equal to zero. Therefore:

$\omega = 0\,\frac{rad}{s}$

7 0

4 years ago

State some important uses of magnet

GarryVolchara [31]

Use of magnet:

Magnets are used in magnetic compass, doorbells, refrigerators.
Magnets are used in dynamos, motors, loudspeakers, microphones etc.
Ceramic magnets are used in computers.
Magnets are used in toys to give a magic effect.

3 0

3 years ago

Read 2 more answers

How many joules of gravitational potential energy does a person have after they went up stairs that are 10 meters tall? Assume t

Sonja [21]

Answer:

P = 5880 J

Explanation:

Given that,

The mass of a person, m = 60 kg

The height of the stairs, h = 10 m

We need to find the gravitational potential energy of the person. The formula is as follows :

$P=mgh$

Substitute all the values,

$P=60\times 9.8\times 10\\\\P=5880\ J$

So, the required gravitational potential energy is equal to 5880 J.

8 0

3 years ago

A petrol engine that transforms 1000J of chemical potential energy into 300J of kinetic energy, and 700J into wasted heat and so

sergey [27]

Answer:

Efficiency = 30% = 0.3

Explanation:

The general formula for efficiency of a device is given as:

Efficiency = (Desired Output/ Input) * 100%

Here, in our case, we have a petrol engine as a device. So, we analyze it for the efficiency calculations. Here, we have:

Chemical Potential Energy = 1000 J

Kinetic Energy = 300 J

Heat and Sound Energy = 700 J

Now, we know that the desired output of a car or the purpose of a car is to provide Kinetic energy, while all other forms of energy such as heat and sound energies are produced as waste. And the chemical energy is provided to car as input, in form of fuel. Therefore,

Input = Chemical Potential Energy = 1000 J

Desired Output = Kinetic Energy = 300 J

Therefore,

Efficiency = (300 J/1000 J) * 100%

<u>Efficiency = 30% = 0.3</u>

4 0

3 years ago