Ask question

Ask question

All categories

3 years ago

12

Se calienta para templar y endurecer, una llave española de acero de 200 gramos, elevando su temperatura hasta los 550°C y se in

troduce dentro de un recipiente de aluminio de 250 gramos de masa que contiene 220 gramos de agua. A 18°C. Determinar la temperatura final, cuando se alcanza el equilibrio térmico. Considere El CeHierro= 0.499cal/g°C; CeAluminio= 0.217cal/g°C; Ce agua=1cal/g°C

1 answer:

DanielleElmas [232]3 years ago

8 0

Answer:

La temperatura final es de aproximadamente 159,94°C

Explanation:

Los parámetros dados son;

La masa de la llave española de acero, m₁ = 200 gramos

La temperatura de la llave, T₁ = 550 ° C

La masa del recipiente de aluminio que contiene agua, m₂ = 250 gramos

La masa del agua en el recipiente de aluminio, m₃ = 220 gramos

La capacidad calorífica específica del hierro, $C_{planchar}$ , c₁ = 0.499 ca/(g·°C)

La capacidad calorífica específica del aluminio, $C_{Aluminio}$ , c₂ = 0.217 cal/(g·°C)

La capacidad calorífica específica del agua, $C_{Agua}$ , c₃= 1 cal/(g·°C)

En equilibrio térmico, tenemos;

m₁·c₁·(T₁ - T) = m₂·c₂·(T -T₂) + m₃·c₃·(T - T₂)

Conectando los valores, da;

200 × 0.499 × (550 - T) = 250 × 0.217 × (T -18) + 220 × 1 × (T - 18)

Simplificando, usando una calculadora gráfica, obtenemos;

$\dfrac{274450-499\cdot T}{5} = \dfrac{1097 \cdot T-19746}{4}$

De también encontramos 'T' al convertirlo en el tema de la ecuación anterior aún usando una calculadora gráfica;

T = 1196530/7481 °C ≈ 159.94°C

La temperatura final,T ≈ 159.94°C.

You might be interested in

In a machining operation that approximates orthogonal cutting, the cutting tool has a rake angle =100 . The chip thickness ratio

Rudik [331]

Answer:

The percentage of the total energy dissipated into shear plane is 89.46%.

Explanation:

Given that,

Rake angle = 10°

Thickness ratio= 0.5

Cutting Force = 400 N

Thrust force = 200 N

Speed =3 m/s

Suppose the shear force is 345.21 N.

We need to calculate the shear plane angle

Using formula shear angle

$\tan\phi=\dfrac{r\cos\alpha}{1-r\sin\alpha}$

Put the value in to the formula

$\tan\phi=\dfrac{0.5\cos10}{1-0.5\sin10}$

$\tan\phi=0.539$

$\phi=\tan^{-1}(0.539)$

$\phi=28.32^{\circ}$

We need to calculate the shear velocity

Using formula of shear velocity

$v_{2}=\dfrac{v\cos\alpha}{\cos(\phi-\alpha)}$

Put the value into the formula

$v_{2}=\dfrac{3\times\cos10}{\cos(28.32-10)}$

$v_{2}=3.11\ m/s$

We need to calculate the percentage of the total energy dissipated into shear plane

Using formula of energy dissipated

$\%d=\dfrac{P_{s}}{P}\times100$

$\%d=\dfrac{F_{s}\times v_{c}}{F_{c}\times v}\times100$

Put the value into the formula

$\%d=\dfrac{345.21\times3.11}{400\times3}\times100$

$d=89.46\%$

Hence, The percentage of the total energy dissipated into shear plane is 89.46%.

6 0

3 years ago

Calculate the recoil speed of a 1.4 kg rifle shooting 0.006 kg bullets with muzzle speed of 800 m/a.3.43 m/s

Angelina_Jolie [31]

Answer:

a) 3.43 m/s

Explanation:

Due to the law of conservation of momentum, the total momentum of the bullet - rifle system must be conserved.

The total momentum before the bullet is shot is zero, because they are both at rest, so:

$p_i = 0$

Instead the total momentum of the system after the shot is:

$p_f = mv+MV$

where:

m = 0.006 kg is the mass of the bullet

M = 1.4 kg is the mass of the rifle

v = 800 m/s is the velocity of the bullet

V is the recoil velocity of the rifle

The total momentum is conserved, therefore we can write:

$p_i = p_f$

Which means:

$0=mv+MV$

Solving for V, we can find the recoil velocity of the rifle:

$V=-\frac{mv}{M}=-\frac{(0.006)(800)}{1.4}=-3.43 m/s$

where the negative sign indicates that the velocity is opposite to direction of the bullet: so the recoil speed is

a) 3.43 m/s

5 0

3 years ago

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

Nesterboy [21]

Answer:

A.) 1372 N

B.) 1316 N

C.) 1428 N

Explanation:

Given that a 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following cases:

a. The load moves downward at a constant velocity

At constant velocity, acceleration = 0

T - mg = ma

T - mg = 0

T = mg

T = 140 × 9.8

T = 1372N

b. The load accelerates downward at a rate 0.4 m/s??

Mg - T = ma

140 × 9.8 - T = 140 × 0.4

1372 - T = 56

-T = 56 - 1372

- T = - 1316

T = 1316N

C. The load accelerates upward at a rate 0.4 m/s??

T - mg = ma

T - 140 × 9.8 = 140 × 0.4

T - 1372 = 56

T = 56 + 1372

T = 1428N

8 0

3 years ago

Suppose the charges attracting each other in the above situation have an equal magnitude. Find the charge.

LiRa [457]

The force between the two point charge when they are separated by 18 cm is 3 N

<h3>How do I determine the force when they are 18 cm apart?</h3>

Coulomb's law states as follow:

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Kq₁q₂ => constant

F₁r₁² = F₂r₂²

Where

F₁ and F₂ are the initial and new force
r₁ and r₂ are the initial and new distance apart

With the above formula, we can obtain the force between the two point charge when they are 18 cm apart. Details below:

Initial distance apart (r₁) = 6 cm
Initial force of attraction (F₁) = 27 N
New distance apart (r₂) = 18 cm
New force of attraction (F₂) =?

F₁r₁² = F₂r₂²

27 × 6² = F₂ × 18²

972 = F₂ × 324

Divide both side by 324

F₂ = 927 / 324

F₂ = 3 N

Thus, the force when they are 18 cm apart is 3 N

Learn more about force:

brainly.com/question/28569085

#SPJ1

7 0

2 years ago

Can someone please help me on number 4......

saw5 [17]

mass/volume = density.

if bigger than water, sinks

less than water floats.

Archimedes' principle, floatation, icebergs etc

7 0

3 years ago

Read 2 more answers