Answer:
+5.7 m/s
Explanation:
According to the law of conservation of momentum is that the momentum before the collision is equal to the momentum after the collision. In an equation form it would look like this:
M₁V₁+M₂V₂ = M₁V₁'+M₂V₂'
Where:
M₁ = mass of object 1 (kg)
V₁ = velocity of object 1 before the collision (m/s)
V₁' = Final velocity of object 1 after the collision (m/s)
M₂ = mass of object 2 (kg)
V₂ = velocity of object 2 before the collision (m/s)
V₂' = Final velocity of object 2 after the collision (m/s)
According to your problem you have the following given:
M₁ = 5 g = 0.005kg
V₁ = 3 m/s
V₁' = -5m/s (It bounced off so it is going the other direction)
M₂ = 6g = 0.006kg
V₂ = -1 m/s (It is coming from the opposite direction of the 3-ball)
V₂' = ?
So we plug in what we know and solve for what we don't know.
Answer:
C and D
Explanation:
Charge on right = +0.001 C
Charge on left = 1000 C
Charge held in between = -1C
Ratio between right and left charge:
Which shows charge on left exerts 1,000,000 times more force then charge on right
Charge on left is 1000 times greater in magnitude than charge held between and charge held between is 1000 times greater in magnitude than charge on right. So the magnitude of the force on the charge you are holding would be the same if it were +1 C instead of −1 C.
Answer:
Conduction heat transfer is the transfer of <em>heat by means of molecular excitement within a material without bulk motion</em> of the matter.
Explanation:
Conduction heat transfer in gases and liquids is due to the collisions and diffusion of the molecules during heir random motion.
<span> we suppose that x be distance of man from spot light is
so 12-x is distance from man to wall
we will draw first triangle ABC, where
a= spotlight (on ground)
b= man (feet)
c= man (head)
we know that AB = x and BC = 2
by extend line AB to the wall at point D and extend line AC to the wall at point E
AD = 12 (distance from spotlight to wall)
DE = s (length of shadow)
Now triangles ABC and ADE are similar
Therefore DE/AD = BC/AB
s / 12 = 2 / x
s = 24 / x
Differentiate both sides with respect to t
ds/dt = -24/x² dx/dt
Man is walking toward building at speed of 16 ms
dx/dt = 16
Man is 4 m from the building/wall
12 - x = 4
x = 8
Find ds/dt when x = 8 and dx/dt = 16
ds/dt = -24/x² dx/dt
ds/dt = -24/(64) * 16
ds/dt = -6
So length of shadow is decreasing at rate of 6 m/s
hope it helps
</span>
Absolute, Atmospheric, Differential, and Gauge Pressure
