Answer: ![62.7^0C](https://tex.z-dn.net/?f=62.7%5E0C)
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
![Q=m\times c\times \Delta T](https://tex.z-dn.net/?f=Q%3Dm%5Ctimes%20c%5Ctimes%20%5CDelta%20T)
Q = Heat absorbed= 16.7 kJ = 16700 J (1kJ=1000J)
m= mass of benzene = 225 g
c = specific heat capacity = 1.74 J/gK
Initial temperature of the water =
= 20.0°C = 293 k ![0^0C=273K](https://tex.z-dn.net/?f=0%5E0C%3D273K)
Final temperature of the water =
= ?
Change in temperature ,![\Delta T=T_f-T_i](https://tex.z-dn.net/?f=%5CDelta%20T%3DT_f-T_i)
Putting in the values, we get:
![16700=225\times 1.74\times (T_f-293)](https://tex.z-dn.net/?f=16700%3D225%5Ctimes%201.74%5Ctimes%20%28T_f-293%29)
![T_f=335.6K=62.7^0C](https://tex.z-dn.net/?f=T_f%3D335.6K%3D62.7%5E0C)
The final temperature will be ![62.7^0C](https://tex.z-dn.net/?f=62.7%5E0C)
Answer:
The density of the woman is 950.8 kg/m³
Explanation:
Given;
fraction of the woman's volume above the surface = 4.92%
then, fraction of the woman's volume below the surface = 100 - 4.92% = 95.08%
the specific gravity of the woman ![= \frac{95.08}{100 } = 0.9508](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B95.08%7D%7B100%20%7D%20%3D%200.9508)
The density of the woman is calculate as;
![Specific \ gravity \ of \ the \ woman = \frac{Density \ of \ the \ woman }{Density \ of \ fresh \ water }\\\\ Density \ of \ the \ woman = Specific \ gravity \ of \ the \ woman \ \times \ Density \ of \ fresh \ water](https://tex.z-dn.net/?f=Specific%20%5C%20gravity%20%5C%20of%20%5C%20the%20%5C%20woman%20%3D%20%5Cfrac%7BDensity%20%5C%20of%20%5C%20the%20%5C%20woman%20%7D%7BDensity%20%5C%20of%20%5C%20fresh%20%5C%20water%20%7D%5C%5C%5C%5C%20Density%20%5C%20of%20%5C%20the%20%5C%20woman%20%20%3D%20Specific%20%5C%20gravity%20%5C%20of%20%5C%20the%20%5C%20woman%20%5C%20%5Ctimes%20%5C%20Density%20%5C%20of%20%5C%20fresh%20%5C%20water)
Density of fresh water = 1000 kg/m³
Density of the woman = 0.9508 x 1000 kg/m³
Density of the woman = 950.8 kg/m³
Therefore, the density of the woman is 950.8 kg/m³
Yes that is a balaned equation
1. B- it can cause cirrhosis
2. C- intoxication
3. A- admit to having a problem with alcohol
4. D- binge-drinking
5. A- depressant
6. true
7. false
(a) The angular acceleration of the wheel is given by
![\alpha = \frac{\omega_f - \omega_i }{t}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%20%5Cfrac%7B%5Comega_f%20-%20%5Comega_i%20%7D%7Bt%7D%20)
where
![\omega_i](https://tex.z-dn.net/?f=%5Comega_i)
and
![\omega_f](https://tex.z-dn.net/?f=%5Comega_f)
are the initial and final angular speed of the wheel, and t the time.
In our problem, the initial angular speed is zero (the wheel starts from rest), so the angular acceleration is
![\alpha = \frac{(11.2 rad/s) - 0}{3.07 s} =3.65 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%20%5Cfrac%7B%2811.2%20rad%2Fs%29%20-%200%7D%7B3.07%20s%7D%20%3D3.65%20rad%2Fs%5E2)
(b) The wheel is moving by uniformly rotational accelerated motion, so the angle it covered after a time t is given by
![\theta (t) = \omega_i t + \frac{1}{2} \alpha t^2](https://tex.z-dn.net/?f=%5Ctheta%20%28t%29%20%3D%20%5Comega_i%20t%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20%5Calpha%20t%5E2%20)
where
![\omega_i = 0](https://tex.z-dn.net/?f=%5Comega_i%20%3D%200)
is the initial angular speed. So, the angle covered after a time t=3.07 s is