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andrezito [222]
3 years ago
5

Question 23 of 32

Physics
1 answer:
-BARSIC- [3]3 years ago
4 0

Answer:

2m/s

     

Explanation:

Given parameters:

Mass of truck  = 9000kg

Kinetic energy = 18000J

Unknown:

Speed  = ?

Solution:

Kinetic energy is the energy due to the motion of a body;

  K.E  = \frac{1}{2} mv²  

 So;

 m is the mass

  v is the speed

   2 KE = mv²

  2 x 18000 = 9000 x v²

     v²  = 4

     v = 2m/s

     

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Consider the following distinct forces:______________________________.
Kamila [148]

Answer:

1 and 2

Explanation:

It is given that, force exerted by air is negligible in any way.

Also, it is given that channel is in the shape of a segment of a circle with its center at O.

When it is within the frictionless channel at position 'Q',

A gravity exerts force on the ball in the downward direction. On the other hand, the channel pointing from Q to O also exerts a force on the ball.

However, there is no any force in the direction of motion. On the other hand, he channel pointing from O to Q does not exert a force on the ball.

5 0
4 years ago
The magnetic field inside a toroid is uniform.<br> a. True<br> b. False
jeyben [28]

The concept that must be applied to solve this problem is that of the magnetic field on Toroid described since the law of Ampere. Mathematically the magnetic field is determined as

B = \frac{\mu_0 NI}{2\pi r}

Where

\mu_0= Permeability constant

N = Number of loops

I = Current

r = Radius

As we can see the magnetic field inside a Toroid is NOT uniform, since it is highly proportional to the radius. Which means that as the radius increases the magnetic field decreases.

Therefore the correct answer is: FALSE

6 0
4 years ago
What do "Newton's apple" and the moon have in common?
SVEN [57.7K]

Answer:

Both these motions are caused by the Gravitational force of earth.

Explanation:

Both these motions are caused by the Gravitational force of earth.

6 0
3 years ago
An ideal monatomic gas at a pressure of 2.0×105N/m2 and a temperature of 300 K undergoes a quasi-static isobaric expansion from
liraira [26]

Answer:

a) W= 400 J

b) T_{2}=600 K

c) n=0.16 mol

d) \Delta E_{int}=598 J

e) Q=998 J

Explanation:

a) Let's recall the definition of work.

W=\int^{Vf}_{V0}PdV

Because the system is a quasi-static isobaric expansion, P is constant here, therefore:

W=P\int^{Vf}_{V0}dV=P(V_{f}-V_{0})

W=2.0\cdot 10^{5}(4.0\cdot 10^{-3}-2.0\cdot 10^{-3})= 400 [Nm^{2}]

b) Using the ideal gas equation we have:

\frac{P_{1}V_{1}}{T_{1}}=nR (1)

and \frac{P_{2}V_{2}}{T_{2}}=nR (2)

We can note that n times R is a constant in (1) and (2), so we can equal those equations.

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}} (3)

Let's solve T₂ for (3), let's recall that P₁ = P₂, so they canceled out

T_{2}=T_{1}\cdot V_{2}/V_{1}

T_{2}=300\cdot 4x10^{3}/2x10^{3}=600 K

c) Using the equation of ideal gas we have:

\frac{P_{1}V_{1}}{RT_{1}}=n

n=\frac{P_{1}V_{1}}{RT_{1}}=0.16 mol

d) We can write the internal energy as a function of Cv, and as we know the Cv is 1.5R for a monoatomic gas.

\Delta E_{int}=n1.5R\Delta T

\Delta E_{int}=0.16\cdot 1.5\cdot 8.3 \cdot (600-300)

\Delta E_{int}=598 J

e) Using the first law of thermodynamic, we have:

\Delta E_{int}=Q-W

Finally,

Q=\Delta E_{int}+W=598+400=998 J

Have a nice day!

3 0
3 years ago
Four 21.2 ω resistors are connected in parallel across a 35.8 v ideal battery. what is the current through the battery?
Alenkinab [10]

The resistors behavelike a single resistor of (21.2/4) = 5.3 ohms.

The total current through the parallel bunch of resistors is E/R = 35.8/5.3 = 6.75 Amperes.

That's the total current SUPPLIED by the battery. Current doesn't flow 'through' a battery.

6 0
3 years ago
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