Answer:
24.325 kg m/s
Explanation:
Initial momentum, pi = 18 kg m/s
F = < -4, 12, 0>
t = 0.5 s
Let the final momentum is pf.
The magnitude of force is
According to the Newton's second law, the rate of change of momentum is equal to the force.
pf - 18 = 6.325
pf = 24.325 kg m/s
Thus, the momentum of body after 0.5 s is 24.325 kg m/s.
Answer:
-19.0 kJ
Explanation:
Let's keep in mind that the direction of the resistive force is always opposite to the displacement of the bicyclist.
- In the first part of the ride:
Displacement: d = 1.86 km = 1860 m
Resistive force: F = 5.12 N
Angle between the direction of the force and the displacement:
So, the work done by the resistive force is
- Similarly, in the second part of the ride:
Displacement: d = 1.86 km = 1860 m
Resistive force: F = 5.12 N
Angle between the direction of the force and the displacement:
So, the work done by the resistive force is
Therefore, the total work done by the resistive force during the round trip is
Given :
A boy walked 22 m East then 43 m West , and then 3 meters East.
To Find :
What is the sum of the boys motion.
Solution :
We need to find the sum of all the motion of boy .
So , we need to find the distance covered by the boy .
We know , total distance covered is absolute sum of all the motion .
Therefore , total distance covered is 68 meters .
Hence , this is the required solution .