Answer:
250+50=300ms-¹
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Answer:
v0x = 104.89 m/s
The vector v0x will be:
v0x = (104.89 m/s, 0)
Explanation:
Please, see the attached figure for a better understanding of the problem.
To obtain v0x, we have to use this trigonometric rule:
cos θ = adjacent / hypotenuse
Seeing the figure, notice that the side adjacent to the angle θ is the x-component of the initial velocity v0. The hypotenuse is the magnitude of the vector v0. Then:
cos θ = magnitude v0x / magnitude v0
magnitude v0 * cos θ = magnitude v0x
151.0 m/s * cos 46 = magnitude v0x
magnitude v0x = 104.89 m/s
The vector v0x will be:
v0x = (104.89 m/s, 0)
Answer:
because
Explanation:
Mass and velocity are both directly proportional to the momentum. If you increase either mass or velocity, the momentum of the object increases proportionally. If you double the mass or velocity you double the momentum.
Answer:
<h2> 27m/s</h2>
Explanation:
Given data
initital velocity u=15m/s
deceleration a=3m/s^2
time t= 4 seconds
final velocity v= ?
Applying the expression
v=u+at------1
substituting our data into the expression we have
v=15+3*4
v=15+12
v=27m/s
The velocity after 4 seconds is 27m/s