Answer:
Three forms of energy when a match is being lit are potential, kinetic and thermal.
hope this helps! :)
Explanation:
you need to use hours to make it easy to convert to m/s. Change 15 minutes to hours
Note distance is in km so change the time to hours to get km/hour
1 hour = 60mins so 15 minutes will be 0.25 hours
10/0.25 = 40 km/ hour
To change that to m/second, change km to meters and hour to second
it will be (40x1000) meters /3600seconds
11.1111 m/s
Answer:
Presión = 175,97 N/m²
Explanation:
Dados los siguientes datos;
Peso del alumno (fuerza) = 725N
Área de zapatos = 412 cm² a metros cuadrados = 412/100 = 4.12 metros
Para encontrar la presión, usaríamos la siguiente fórmula;
Presión = fuerza / área
Presión = 725 / 4.12
Presión = 175,97 N/m²
Answer:
505.62 mm
Explanation:
Young's modulus of a material is given by,

Stress is the force experienced by the material per unit area (which is why stress has the same units as pressure).
Strain is the ratio between the change in length/area/volume to the original length/area/volume of the material (and hence a dimensionless quantity). Basically, it gives us a measure of the change in dimensions due to the stress experienced.
So, for the given problem,

or,
(since we need to find the compression of the bone at the critical stress point)
or, 
Answer:
a) 1.6*10^6 V
b) 13.35*10^6 V
Explanation:
The electric potential at origin is the sum of the contribution of the two charges. You use the following formula:
(1)
q1 = 3.90µC = 3.90*10^-6 C
q2 = -2.4µC = -2.4*10^-6 C
r1 = 1.25 cm = 0.0125 m
r2 = -1.80 cm = -0.018 m
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
You replace all the parameters in the equation (1):
![V=k[\frac{q_1}{r_1}+\frac{q_2}{r_2}]\\\\V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0125m}+\frac{-2.4*10^{-6}C}{0.018m}]=1.6*10^6V](https://tex.z-dn.net/?f=V%3Dk%5B%5Cfrac%7Bq_1%7D%7Br_1%7D%2B%5Cfrac%7Bq_2%7D%7Br_2%7D%5D%5C%5C%5C%5CV%3D%288.98%2A10%5E9Nm%5E2%2FC%5E2%29%5B%5Cfrac%7B3.90%2A10%5E%7B-6%7DC%7D%7B0.0125m%7D%2B%5Cfrac%7B-2.4%2A10%5E%7B-6%7DC%7D%7B0.018m%7D%5D%3D1.6%2A10%5E6V)
hence, the total electric potential is approximately 1.6*10^6 V
b) For the coordinate (1.50 cm , 0) = (0.015 m, 0) you have:
r1 = 0.0150m - 0.0125m = 0.0025m
r2= 0.015m + 0.018m = 0.033m
Then, you replace in the equation (1):
![V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0025m}+\frac{-2.4*10^{-6}C}{0.033m}]=13.35*10^6V](https://tex.z-dn.net/?f=V%3D%288.98%2A10%5E9Nm%5E2%2FC%5E2%29%5B%5Cfrac%7B3.90%2A10%5E%7B-6%7DC%7D%7B0.0025m%7D%2B%5Cfrac%7B-2.4%2A10%5E%7B-6%7DC%7D%7B0.033m%7D%5D%3D13.35%2A10%5E6V)
hence, for y = 1.50cm you obtain V = 13.35*10^6 V