Answer:- 171 g
Solution:- It asks to calculate the grams of sucrose required to make 1 L of 0.5 Molar solution of it.
We know that molarity is moles of solute per liter of solution.
If molarity and volume is given then, moles of solute is molarity times volume in liters.
moles of solute = molarity* liters of solution
moles of solute = 0.5*1 = 0.5 moles
To convert the moles to grams we multiply the moles by molar mass.
Molar mass of sucrose = 12(12) + 22(1) + 11(16)
= 144 + 22 + 176
= 342 grams per mol
grams of sucrose required = moles * molar mass
grams of sucrose required = 0.5*342 = 171 g
So, 171 g of sucrose are required to make 1 L of 0.5 molar solution.
Proton: positive- mass equal to neutron
Electron: negative- mass 1/1840 mass of proton
Neutron: no charge- same mass as proton
1 pound of coffee is said to yield 50 cups of coffee
So we need to find the pounds of coffee beans required to produce 250 cups
so if 50 cups need 1 pound of coffee beans
therefore 250 cups need - 1/50 x 250 = 5 pounds of coffee beans
since we have to find the amount of coffee beans needed in kg, we have to convert pounds to kg
1 pound = 0.45 kg
So if 1 pound is equivalent to 0.45 kg
then 5 pounds are equivalent to - 0.45 kg/pound x 5 pounds = 2.25 kg
therefore 2.25 kg of coffee beans are required
A compound machine is that which is composed of two or more simple machines. Simple machines come in 6 basic types: (1) wheel and axle, (2) inclined plane, (3) wedge, (4) pulley, (5) screw, and (6) lever. Among the choices given above, the compound machine is the can opener for it is a combination of a wedge and a lever.
