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3 years ago

Whats funnier than 24?

Physics

1 answer:

KonstantinChe [14]3 years ago

8 0

25 lololololololololololololol

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5. The net external force on a rock of mass 4.2 kg is 8.0 N forward. Find the acceleration of the rock.

andreev551 [17]

Answer:

1.904

Explanation:

F= ma

8 = 4.2 a

a = 8/4.2

a = 1.904

6 0

2 years ago

On a caterpillars map all distances are marked in kilometers . The caterpillars map shows the distance between two milkweed plan

frutty [35]

Answer:

The distance in kilometers is 4012 × $10^{-6}$ km.

Explanation:

We know that the conversion of 1 millimeters is equal to $10^{-3}$ meter. And then the conversion of 1 meter is equal to $10^{-3}$ km. Then the conversion of 1 millimeter to km will be

1 mm = $10^{-3}$ m

1 m = $10^{-3}$ km

So, 1 mm = $10^{-3}$ × $10^{-3}$ km = $10^{-6}$ km.

As here the the distance is 4012 mm, then the distance in km will be

4012 mm = 4012 × $10^{-6}$ km.

So the distance is 4012 × $10^{-6}$ km.

5 0

3 years ago

Timed plz hurry

puteri [66]

Answer:

Explanation:

emphasizes self-importance

4 0

3 years ago

Read 2 more answers

a child pulls on a string that is attached to a car. if the child does 80.2 J of work while pulling the car 25.0 m, with what fo

12345 [234]

Answer:

F = 3.20 N

Explanation:

Given:

Work done by child = 80.2 j

Distance that the car moves = 25.0 m

We need to find the force acting on the car.

Solution:

Using work done formula as.

$W = F\times d$

Where:

W = Work done by any object.

F = Force (push or pull)

d = distance that the object moves.

Substitute $W = 80.2\ J\ and\ d =25.0\ m$ in work done formula.

$80.2 = F\times 25$

$F=\frac{80.2}{25}$

F = 3.20 N

Therefore, force acting on the car F = 3.20 N

3 0

3 years ago

At time t=0 , in your frame of reference Z, you measure the back of the spaceship to be at x=0 and the front of the ship to be a

Liula [17]

An equation relating the length that you measure l to the ship's proper length l0 is

l =l0/y. This is further explained below.

<h3>What is an equation relating the length that you measure l to the ship's proper length l0?</h3>

Generally, Any object's length in a moving frame will look shortened or contracted when seen in that direction. The Lorentz transformation may be used to determine the amount of contraction.

In conclusion, To use the Lorentz Lorentz transformation, the length Lo-x2 - may be determined if it is measured in the moving reference frame. Hence the Resultant l = l0/y.