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3 years ago

8

what is the maximum distance we can shoot a dart,from ground level provided our toy dart gun gives a maximum initial velocity of

2.7m/s and air resistance is negligible

1 answer:

mestny [16]3 years ago

3 0

Answer:

R = v^2 sin 2 theta / g

The range provides the distance a projectile can travel

R(max) = v^2 / g if theta = 45 deg

R = 2.7^2 / 9.8 = .74 m

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What is the resistivity of a wire of 1.3 mm diameter, 2.3 m length, and 61 ms resistance. Number Units The number of significant

kakasveta [241]

Answer:

$\rho = 3.68 *10^{-8} Ω. m$

Explanation:

The resistance is given as

$R = \frac{\rho L}{A}$

Where A IS Cross sectional area of wire $= \pi r^{2}$

therefore resistivity \rho can be wrtten as

$\rho = \frac{\pi Rd^{2}}{4L}$

Putting all value to get resistivity value $\rho =\frac{\pi* 61*10^{-3}* (1.33*10^{-3})^{2}}{4*2.3}$

$\rho = 3.68 *10^{-8} Ω. m$

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4 years ago

A car travels 20 km South, then turns and travels 30 km East? What is the total displacement?

Ne4ueva [31]

Answer:

Explanation:36.05 km

Given

First car travels $r_1=20\ km$ South

then turns and travels $r_2=30\ km$ east

Suppose south as negative y axis and east as positive x axis

So, $r_1=-20\hat{j}$

$r_2=30\hat{i}$

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Dispalcement $=r=r_1+r_2$

Displacement $=-20\hat{j}+30\hat{i}$

Displacement $=30\hat{i}-20\hat{j}$

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3 years ago

What would the charge be on an ion with 8 protons 7 neutrons and 6 elements?

andre [41]

Answer:

-2

Explanation:

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3 years ago

What is the chemical formula for ammonium hydroxide

hoa [83]

NH4OH is the answer. Hope this helps you.

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3 years ago

A steel tank of weight 600 lb is to be accelerated straight upward at a rate of 1.5 ft/sec2. Knowing the magnitude of the force

VikaD [51]

Answer:

a) the values of the angle α is 45.5°

b) the required magnitude of the vertical force, F is 41 lb

Explanation:

Applying the free equilibrium equation along x-direction

from the diagram

we say

∑Fₓ = 0

Pcosα - 425cos30° = 0

525cosα - 368.06 = 0

cosα = 368.06/525

cosα = 0.701

α = cos⁻¹ (0.701)

α = 45.5°

Also Applying the force equation of motion along y-direction

∑Fₓ = ma

Psinα + F + 425sin30° - 600 = (600/32.2)(1.5)

525sin45.5° + F + 212.5 - 600 = 27.95

374.46 + F + 212.5 - 600 = 27.95

F - 13.04 = 27.95

F = 27.95 + 13.04

F = 40.99 ≈ 41 lb

8 0

3 years ago