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Butoxors [25]
3 years ago
8

what is the maximum distance we can shoot a dart,from ground level provided our toy dart gun gives a maximum initial velocity of

2.7m/s and air resistance is negligible​
Physics
1 answer:
mestny [16]3 years ago
3 0

Answer:

R = v^2 sin 2 theta / g

The range provides the distance a projectile can travel

R(max) = v^2 / g    if theta = 45 deg

R = 2.7^2 / 9.8 = .74 m

You might be interested in
If you apply an unbalanced force to this object it will ______. Mention all that will apply: change velocity, accelerate, change
Papessa [141]

Answer:

All of them: change velocity, accelerate, change position

Explanation:

We can answer this question by using Newton's second law:

F = ma

where

F is the net force on the object

m is the mass of the object

a is the acceleration

We notice that when there is an unbalanced force on the object, F\neq 0, and therefore

a\neq 0

whcih means that the object will accelerate.

But acceleration is the rate of change of velocity, v:

a=\frac{\Delta v}{\Delta t}

And so,

\Delta v \neq 0

which means that the object will change velocity.

If the object is changing velocity, this means that it is also moving: therefore, the position of the object must be changing, so also the option "change position" is correct.

6 0
3 years ago
In a maneuver, the jet comes in for a landing on solid ground with a speed of 115 m/s, and its acceleration can have a maximum m
V125BC [204]

Answer:

17.1130952381 s

No

Explanation:

t = Time taken

u = Initial velocity = 115 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -6.72 m/s² (negative as it is decelerating)

From the equations of motion

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-115}{-6.72}\\\Rightarrow t=17.1130952381\ s

The minimum time required to stop is 17.1130952381 s

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-115^2}{2\times -6.72}\\\Rightarrow s=984.00297619\ m

The distance that is required for the jet to stop is 0.98400297619 km which is greater than 0.8 km. So, the jet cannot land on a small tropical island airport.

4 0
3 years ago
Please somebody help i took screenshot ik there is a blank space but look down a little
Dahasolnce [82]

Answer:

Force has a direct relationship to mass and acceleration. Newton's Second Law, force equals mass times acceleration (F=MA), illustrates their general relationship in an equation.

Explanation:

Relationships to remember:

  • <u>Force</u> and <u>acceleration</u> have a direct relationship, meaning if force increases, acceleration will also increase and vice versa

(Ex: The harder you push a box, the faster it will move)

  • <u>Mass</u> and <u>acceleration</u> have an inverse relationship, meaning if mass increases, acceleration will <em>decrease</em> and vice versa

(Ex: If you add more furniture in the back of a moving company truck, the truck will move slower than it did before the furniture was added)

  • <u>Force</u> and <u>mass</u> have a direct relationship, meaning if mass increases, force will also increase

(Ex: You will need to exert less force to lift a 5-pound weight than a 10-pound weight)

And of course, Newton's Second Law, F=MA sums all of this up in 3 letters and a symbol! If you have any more questions about this problem, please comment on my answer :)

6 0
3 years ago
¿A qué velocidad debe circular un auto de carreras para recorrer 87 km en 20 min? (pasar a metros por segundo m/s)
Alexxx [7]

Answer:

Velocidad en m / s = 72,25 m / s

Explanation:

Dado

Distancia a recorrer por el coche de carreras = 87 Km

1 km = 1000 m

Por lo tanto, 87 km = 87000 m

Tiempo necesario para viajar 87 km / 87000 metros = 20 minutos o 20 * 60 = 1200 segundos

Velocidad en m / s = 87000/1200

Velocidad en m / s = 72,25 m / s

7 0
3 years ago
A man of mass 81 kg escapes from a burning building by jumping from a window situated 32 m above a catching net. The acceleratio
Dafna1 [17]

Answer:

The speed of man before he hits the ground is <u>23.35 m/s</u>

Explanation:

We know that:

Weight of Man - Force of Friction = Unbalanced Force

but, from Newton's 2nd Law of Motion:

unbalanced force = ma

Therefore,

W - F = ma

a = (W - F)/m

a = (mg - F)/m

where,

m = 81 kg

g = 9.8 m/s²

F = 103 N

a = [(81 kg)(9.8 m/s²) - 103 N]/81 kg

a = 8.52 m/s²

using 3rd equation of motion:

Vf² - Vi² = 2ah

here,

Vi = initial velocity = 0 m/s

Vf = Final Velocity before he hits ground = ?

Vf² - 0² = 2(8.52 m/s²)(32 m)

Vf = √545.28 m²/s²

<u>Vf = 23.35 m/s</u>

4 0
3 years ago
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