Paauto A: Isulat sa papel ang alpabetong Ingles at bilang I hanggang 10 sa istilong
1 answer:
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Answer:
The kinetic energy of the merry-goround after 3.62 s is 544J
Explanation:
Given :
Weight w = 745 N
Radius r = 1.45 m
Force = 56.3 N
To Find:
The kinetic energy of the merry-go round after 3.62 = ?
Solution:
Step 1: Finding the Mass of merry-go-round
m = 76.02 kg
Step 2: Finding the Moment of Inertia of solid cylinder
Moment of Inertia of solid cylinder I =
Substituting the values
Moment of Inertia of solid cylinder I
=>
=>
=>
Step 3: Finding the Torque applied T
Torque applied T =
Substituting the values
T =
T = 81.635 N.m
Step 4: Finding the Angular acceleration
Angular acceleration ,
Substituting the values,
Step 4: Finding the Final angular velocity
Final angular velocity ,
Substituting the values,
Now KE (100% rotational) after 3.62s is:
KE =
KE =
KE = 544J
Answer:
The kinetic coefficient of friction between the box and the floor is 1.020.
Explanation:
Let suppose that box is on horizontal ground. According to the Newton's Laws, an object has a net acceleration of zero when either is at rest or moves at constant velocity. Friction is a reaction to the external force that moves the box. Hence, the equation of equilibrium for the 20-Kg box is:
(Eq. 1)
Where:
- External force, measured in newtons.
- Friction force, measured in newtons.
If we know that , then the magnitude of the kinetic friction force is:
In addition, friction force is represented by the following formula:
(Eq. 2)
Where:
- Kinetic coefficient of friction, dimensionless.
- Mass, measured in kilograms.
- Gravitational acceleration, measured in meters per square second.
Now we clear the kinetic coefficient of friction:
If we know that ,
and
, then the kinetic coefficient of friction is:
The kinetic coefficient of friction between the box and the floor is 1.020.