Answer:
Second order line appears at 43.33° Bragg angle.
Explanation:
When there is a scattering of x- rays from the crystal lattice and interference occurs, this is known as Bragg's law.
The Bragg's diffraction equation is :
.....(1)
Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.
Given :
Wavelength, λ = 1.4 x 10⁻¹⁰ m
Bragg's angle, θ = 20°
Order of constructive interference, n =1
Substitute these value in equation (1).
![1\times1.4\times10^{-10} =2d\sin20](https://tex.z-dn.net/?f=1%5Ctimes1.4%5Ctimes10%5E%7B-10%7D%20%3D2d%5Csin20)
d = 2.04 x 10⁻¹⁰ m
For second order constructive interference, let the Bragg's angle be θ₁.
Substitute 2 for n, 2.04 x 10⁻¹⁰ m for d and 1.4 x 10⁻¹⁰ m for λ in equation (1).
![2\times1.4\times10^{-10} =2\times2.04\times10^{-10} \sin\theta_{1}](https://tex.z-dn.net/?f=2%5Ctimes1.4%5Ctimes10%5E%7B-10%7D%20%3D2%5Ctimes2.04%5Ctimes10%5E%7B-10%7D%20%5Csin%5Ctheta_%7B1%7D)
![\sin\theta_{1} =0.68](https://tex.z-dn.net/?f=%5Csin%5Ctheta_%7B1%7D%20%3D0.68)
<em>θ₁ </em>= 43.33°
Answer:
zero
Explanation:
Acceleration is a measure of the rate of change of velocity. If the velocity is unchanging, its rate of change is zero.
The acceleration is zero.
Answer:
40 N
Explanation:
We are given that
Speed of system is constant
Therefore, acceleration=a=0
Tension applied on block B=T=50 N
Friction force=f=10 N
We have to find the friction force acting on block A.
Let T' be the tension in string connecting block A and block B and friction force on block A be f'.
For Block B
![T-f-T'=m_Ba](https://tex.z-dn.net/?f=T-f-T%27%3Dm_Ba)
Where
=Mass of block B
Substitute the values
![50-10-T'=m_B\times 0=0](https://tex.z-dn.net/?f=50-10-T%27%3Dm_B%5Ctimes%200%3D0)
![T'==40 N](https://tex.z-dn.net/?f=T%27%3D%3D40%20N)
For block A
![T'-f'=m_Aa](https://tex.z-dn.net/?f=T%27-f%27%3Dm_Aa)
Where
Mass of block A
Substitute the values
![40-f'=m_A\times 0=0](https://tex.z-dn.net/?f=40-f%27%3Dm_A%5Ctimes%200%3D0)
![f'=40 N](https://tex.z-dn.net/?f=f%27%3D40%20N)
Hence, the friction force acting on block A=40 N