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Marina86 [1]
3 years ago
5

Help please I'll mark as brainliest for the first correct answer​

Physics
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

first one i think is this. work = 1/2 kx^2 = 1/2 Fx

2nd, is 0.08 J

Explanation:

EE = ½ kx²

EE = ½ (400 N/m) (0.02 m) ²

EE = 0.08.

THIRD, Velocity of the stone is 4 m/s when it leaves catapult.

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Sound waves travel at the rate of 343 m/s at 20°C. If a man standing 450 meters away from the wall of a canyon yells, “Hello,” h
nekit [7.7K]

Answer:

2.62seconds

Explanation:

Speed is defined as the ratio of the distance covered by a body with respect to time.

Speed v = Distance (s)/Time (t)

For a traveling sound wave, the distance between the source of a sound and the reflector is '2S'.

Speed v = 2 × distance (S)/Time (T)

V = 2S/t

2S = vt

Given speed of the wave = 342m/s

Distance covered = 450m

t = 2S/v

t = (2×450)/343

t = 900/343

t = 2.62seconds

It will take him 2.62seconds for him to hear his own voice echo off of the wall.

5 0
3 years ago
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What do you want us to anwser
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How are physical and chemical changes similar?
Musya8 [376]
Physical and chemical changes are similar because matter experiences a change in state while undergoing either change.
4 0
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The uniform 100-kg I-beam is supported initially by its end rollers on the horizontal surface at A and B. by means of the cable
Ann [662]

I attached a free body diagram for a better understanding of this problem.

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8 0
3 years ago
4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.
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Answer: (a)part:545nm multiply by 0.440m=239.8JEWELS(J)

(B):1/2MULTIPLY BY MVSQUARE(APPLY THE FORMULA OF KINETIC ENERGY)REARANGE THE FORMULA,V=2.13MS

Explanation:

SO FOR PART A, IN ORDER TO CALCULATE THE WORK DONE YOUR SUPPOSE TO APPLY THE FORMULA FORCE MULTIPLY BY DISTANCE WHICH IS THE FORMULA FOR WORK DONE,IN THIS SCENARIO YOU HAD A FORCE OF 545NM AND A DISANCE OF 0.440,SO I ORDER TO FIND THE WORK DONE WE MULTIPLIED THEM BOTHE ACCORDING TO THE FORMULA AND GOT THE ANSWER.

FOR PARTB,I JUST SIMPLY APPLIED THE FORMULA FOR KINETIC ENERGY AND SIMPLY REARRANGED IT IN ORDER TO FIND THE VELOCITY.I MADE V THE SUBJECT OF THE FORMULA.

3 0
2 years ago
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