Answer:
f = 347.08 N
Explanation:
The frictional force exerted by the floor on the refrigerator is given as follows:

where,
f = frictional force = ?
μ = coefficient of static friction = 0.58
W = Weight of refrigerator = mg
m = mass of refrigerator = 61 kg
g = acceleration due to gravity = 9.81 m/s²
Therefore,

<u>f = 347.08 N</u>
Answer:
true b and c
Explanation:
n the electromechanical transitions of the atoms the relationship must be fulfilled
= R (1 / nf - 1 / no²)
where for the final state nf = 1 giving in the case of hydrogen the Lymma series whose smallest wavelength is lam = 122 nm with nf = 1 and there are a series of spectral lines for each value of n of the final state
in the case of sodium so well it has a transition from an excited state to the kiss state (bad)
Now let's review the different proposals
a) False. The electronic potential for sodium is much lower than for hydrognosia
b) True
c) True
d) true
Answer:
4.36 seconds
Explanation:
According to the question;
- Force is 550 N
- Mass of the car is 1200 kg
- Velocity of the car is 2.0 m/s
We are needed to find the time the car must the tow track pull the car.
- From Newton's second law of motion;
- Impulsive force, F = Mv÷t , where m is the mass, v is the velocity and t is the time.
Rearranging the formula;
t = mv ÷ F
Thus;
Time = (1200 kg × 2.0 m/s²) ÷ 550 N
= 4.36 seconds
Thus, the time needed to pull the car is 4.36 seconds
Answer:
Her measurements will be more accurate if she uses a cloth tape
measure instead of a ruler.
Explanation: (apex)
<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>-</u><u>1</u><u>:</u><u>-</u>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>2</u>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>3</u>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>4</u>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>5</u>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>6</u>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>7</u>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>8</u>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>9</u>

<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u><u>10</u>
