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Oksana_A [137]
3 years ago
9

What some nonexamples of diffractions

Physics
1 answer:
Julli [10]3 years ago
5 0

Dispersion, refraction, reflection, propagation, violation, distraction, reaction, acceleration, attenuation, clarification, obfuscation, bloviation, attraction, reception, concentration, rarefaction, evaporation, contraction, accumulation, evisceration, ovulation, lactation, fascination, ejaculation, fertilization, fermentation, intoxication, gravitation, nucleation, publication, privatization, quotation, plagiarization, composition, satiation, tintinnabulation, emasculation, matriculation, graduation, and discussion, are a few examples of NOT diffraction.

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What is the least force you could exert on the refrigerator to move it?
Ulleksa [173]
 <span>If the refrigerator weights 1365 and you are not exerting any vertical force on it, then the normal force is also 1365N. so Fn=1365 

Fsf = Static frictional force = (coefficient of static friction) * (Normal force) 

So the least for you could exert to move it is equal to the Fsf. 
Fsf = (0.49)(1365N)</span><span>
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8 0
3 years ago
What minimum distance should you separate two sources emitting the same waves with wavelength 5mm in phase such that you obtain
Makovka662 [10]

To solve this problem we will apply the concept related to destructive interference (from the principle of superposition). This concept is understood as a superposition of two or more waves of identical or similar frequency that, when interfering, create a new wave pattern of less intensity (amplitude) at a point called a node. Mathematically it can be described as

d = n \frac{\lambda}{2}

Where,

d = Path difference

\lambda= wavelength

n = Any integer which represent the number of repetition of the spectrum

In this question the distance between the two source will be minimum for the case of minimum path difference, then n= 1

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d = 2.5mm

Therefore the minimum distance that should you separate two sources emitting the same waves is 2.5mm

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4 years ago
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you're so beautiful!

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4 0
3 years ago
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3 years ago
An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s . Suppose that
RUDIKE [14]

Answer:

0.0241875 m

Explanation:

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m_2 = Mass of football = 0.43 kg

v_1 = Velocity of quarterback

v_2 = Velocity of football = 15 m/s

Time taken = 0.3 seconds

In this system as the linear momentum is conserved

m_1v_1+m_2v_2=0\\\Rightarrow v_1=-\frac{m_2v_2}{m_1}\\\Rightarrow v_1=-\frac{0.43\times 15}{80}\\\Rightarrow v_1=0.080625\ m/s

Assuming this velocity is constant

Distance=Velocity\times Time\\\Rightarrow Distance=0.080625\times 0.3\\\Rightarrow Distance=0.0241875\ m

The distance the quarterback will move in the horizontal direction is 0.0241875 m

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3 years ago
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