Question

According to the following reaction, how many moles of calcium chloride will be formed upon the complete reaction of 27.9 grams of calcium hydroxide with excess hydrochloric acid? calcium hydroxide (aq) + hydrochloric acid (aq) calcium chloride (aq) + water (l) moles calcium chloride

Answer 1

Answer: 0.377 moles of calcium chloride will be formed.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$    

$\text{Moles of} Ca(OH)_2=\frac{27.9g}{74g/mol}=0.377moles$

The balanced chemical reaction is:

$Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O$  

According to stoichiometry :  

As 1 mole of $Ca(OH)_2$ give = 1 mole of $CaCl_2$

Thus 0.377 moles of $Ca(OH)_2$ give =$\frac{1}{1}\times 0.377=0.377moles$  of $CaCl_2$  

Thus 0.377 moles of calcium chloride will be formed upon the complete reaction of 27.9 grams of calcium hydroxide with excess hydrochloric acid