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QveST [7]
3 years ago
13

What happen to kinetic energy of a body if it speed is doubled​

Physics
1 answer:
Sergio039 [100]3 years ago
4 0

Answer:

The energy possessed by a body because of its motion, equal to one half the mass of the body times the square of its speed is called its kinetic energy. Hence, when velocity is doubled, kinetic energy becomes 4 times.

Explanation:

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A metallic conductor has a resistivity of 35 × 10 −6 Ω⋅m. What is the resistance of a piece that is 20 m long and has a uniform
Nitella [24]

Answer:

Therefore the resistance of the conductor is 175Ω

Explanation:

Resistance:

  • Resistance of a metallic conductor is directly proportional to its length(l).
  • Resistance of a metallic conductor is inversely proportional to its cross section area(A).

The notation sign of resistance is R.

The unit of resistance is ohm (Ω).

Therefore,

R \propto l

and

R \propto \frac{1}{A}

\therefore R\propto \frac{l}{A}

\Rightarrow R=\rho \frac{l}{A}

ρ is the proportional constant.

It is also known as resistivity of that metal.

Given ρ=35×10⁻⁶Ω-m

l= 20 m

A= 4.0×10⁻⁶m²

\therefore R=35\times 10^{-6}\times \frac{20}{4.0\times 10^{-6}}

       =175Ω

Therefore the resistance of the conductor is 175Ω

3 0
3 years ago
A 6kg rock rolls down a hill with a momentum of 12kg m/s . Work out the velocity of the rock
Nat2105 [25]

Answer:

if you need to get the work=force×displacement or if you need the velocity=displacement÷time taken

7 0
3 years ago
Read 2 more answers
A large mass collides with a stationary, smaller mass. How will the masses behave if the collision is inelastic?
iragen [17]
Logically both masses will collide and well make a reaction. first of all depending on the small mass it will either merge or unite with the big mass or it will bounce away from it . if this happen it will make a reaction that will affect both masses. Hope this helps if it is incorrect please let me know :) 

3 0
3 years ago
an electric current of 285.0 ma flows 674. milliseconds. Calculate the amount of electric charge transported. Be sure your answe
yulyashka [42]

Answer:

<em>The amount of electric charge transported = 0.192 C</em>

Explanation:

Electric Charge: This is defined as the product of electric current and time in an electric circuit, The S.I unit of electric charge is Coulombs (C)

Q = It..................... Equation 1

Where Q = Electric charge, I = electric current, t = time.

<em>Given:</em> I = 285 mA, t = 674 milliseconds.

<em>Conversion: (i) Convert from 285 mA to A = (285/1000) A = 0.285 A</em>

<em>       (ii) convert from 674 milliseconds to seconds = (674/1000) s = 0.674 s          </em>

Substituting these values into equation 1

Q = 0.285 × 0.674

<em>Q = 0.192 C</em>

<em>Therefore the amount of electric charge transported = 0.192 C</em>

<em></em>

<em></em>

5 0
3 years ago
The water in a river flows uniformly at a constant speed of 2.50 m/s between parallel banks 80.0 m apart. You are to deliver a p
NISA [10]

Answer:

a)  The swimmer should travel perpendicular to the bank to minimize the spent in getting to the other side.

b) 133.33 m

c) 53.13°

d) 106.67 m

Explanation:

a) The swimmer should travel perpendicular to the bank to minimize the spent in getting to the other side.

b) velocity = distance * time

Let the velocity of the swimmer be v_{s} = 1.5 m/s

The separation of the two sides of the river, d = 80 m

The time taken by the swimmer to get to the other end of the river bank,

t = \frac{d}{v_{s} }

t = 80/1.5

t = 53.33 s

The swimmer will be carried downstream by the river through a distance, s

Let the velocity of the river be v_{r} = 2.5 m/s

S = v_{r} t

S = 53.33 * 2.5

S = 133.33 m

c) To minimize the distance traveled by the swimmer, his resultant velocity must be perpendicular to the velocity of the swimmer relative to water

That is ,

cos \theta = \frac{v_{s} }{v_{r} } \\cos \theta = 1.5/2.5\\cos \theta = 0.6\\\theta = cos^{-1} 0.6\\\theta = 53.13^{0}

d) Downstream velocity of the swimmer, v_{y} = v_{s} sin \theta\\

v_{y} = 1.5 sin 53.13\\v_{y} = 1.2 m/s

The vertical displacement is given by, y = v_{y} t

80 = 1.2 t

t = 80/1.2

t = 66.67 s

the horizontal speed,

v_{x} = 2.5 - 1.5cos53.13\\v_{x} = 1.6 m/s

The downstream horizontal distance of the swimmer, x = v_{x} t

x = 1.6 * 66.67

x = 106.67 m

7 0
3 years ago
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