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avanturin [10]
3 years ago
12

Phosphorous is prepared according to the following equation: Ca3(PO4)2 + 3SiO2 + 5C = 3CaSiO3 +5CO + 2P

Chemistry
1 answer:
ivann1987 [24]3 years ago
6 0

Answer:

48546.7kg or 48546745g

Explanation:

so from this u can work out the amount of moles in phosphorous by doing mass / mr you have to convert the mass in kg to g so you times it by 1000. then divide it by 31 which is the mr of phosphorous. then u can use the molar ratio which is 2:1 . Then use the equation mass= moles*mr

so 97000*1000/31=312903moles

2:1

so 312903/2=156451 moles of ca3(PO4)2

so mass= moles*mr

156451*310.3=48494g

hope this helps u to understand(*°▽°*)

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marshall27 [118]
C is the correct answer
7 0
2 years ago
Which of these elements is a transition metal? francium (Fr) beryllium (Be) chromium (Cr) gallium (Ga) bismuth (Bi)
vitfil [10]
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8 0
3 years ago
Which statement is incorrect regarding the reaction of benzene with an electrophile? View Available Hint(s) A) The carbocation i
Leno4ka [110]

Answer:

The carbocation intermediate reacts with a nucleophile to form the addition product.

Explanation:

The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.

The general mechanism is shown in the figure.

i) Attack of the electrophile on the benzene (which is the nucleophile)

ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.

iii) the carbocation formation is the rate determining step.

iv) There is no formation of addition product.

Thus the wrong statement is

The carbocation intermediate reacts with a nucleophile to form the addition product.

3 0
4 years ago
You are using a standardized 0.1250 M solution of sodium hydroxide to determine the concentration of sulfuric acid. After pipett
Sergeu [11.5K]

Answer: Thus the concentration of the sulfuric acid is 0.1201 M

Explanation:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=10.00mL\\n_2=1\\M_2=0.1250M\\V_2=19.22mL

Putting values in above equation, we get:

2\times M_1\times 10.00=1\times 0.1250\times 19.22\\\\M_1=0.1201M

Thus the concentration of the sulfuric acid is 0.1201

4 0
3 years ago
Unknown substance is heated from 10 celsius to 25 celsius, what happens at 17 Celsius
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At 17 celsius ❤️

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3 years ago
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