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krok68 [10]
3 years ago
14

Mercury is added to a cylindrical container to a depth d and then the rest of the cylinder is filled with water.

Physics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Answer:

0.05m

Explanation:

Density of water = ρ(w) = 1000 kg/ m³ ;  

Density of Mercury = ρ(m) = 13628.95 kg/ m³  

Total pressure at bottom of cylinder=1.1atm

Therefore, pressure due to water and mercury =1.1-1 =atm

0.1atm=10130pa

The pressure at the bottom is given by,

ρ(w) x g[0.4 - d] + ρ(m) x g x d  = 10130

1000 x 9.8[0.4 - d] + 13628.95 x 9.8 d = 10130

3924 - 9810d + 133416d= 10130

123606d= 6206

d= 6202/123606

d= 0.05m

Depth of mercury alone =  d = 0.05m

pshichka [43]3 years ago
3 0

Answer:

0.05 m

Explanation:

Detailed explanation and calculation is shown in the image below.

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Answer:

Angular speed will reach 6.833rad/s before the coin starts slipping

Explanation:

There is no question but I'll asume the common one: Calculate the speed of the turntable before the coin starts slipping.

With a sum of forces:

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Ff=m*V^2/R

At this point, friction force is maximum, so:

\mu*N=m*V^2/R

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V=\sqrt{\mu*g*R}

V=1.025 m/s

The angular speed of the turntable will be:

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3 years ago
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Answer:

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8 0
4 years ago
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A constant net force is applied to an object. Suddenly, the object's mass doubles, but the net force remains the same. For this
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<u>D: Half</u>

We know that,

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In the first case, we observed that a1 = F/m.

In the second case, we observed that the mass has been doubled, so a2 = F/2m .

By the ratio of the two cases, we get

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Answer:

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W = (750\,W)\cdot (3600\,s)

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