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krok68 [10]
3 years ago
14

Mercury is added to a cylindrical container to a depth d and then the rest of the cylinder is filled with water.

Physics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Answer:

0.05m

Explanation:

Density of water = ρ(w) = 1000 kg/ m³ ;  

Density of Mercury = ρ(m) = 13628.95 kg/ m³  

Total pressure at bottom of cylinder=1.1atm

Therefore, pressure due to water and mercury =1.1-1 =atm

0.1atm=10130pa

The pressure at the bottom is given by,

ρ(w) x g[0.4 - d] + ρ(m) x g x d  = 10130

1000 x 9.8[0.4 - d] + 13628.95 x 9.8 d = 10130

3924 - 9810d + 133416d= 10130

123606d= 6206

d= 6202/123606

d= 0.05m

Depth of mercury alone =  d = 0.05m

pshichka [43]3 years ago
3 0

Answer:

0.05 m

Explanation:

Detailed explanation and calculation is shown in the image below.

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