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deff fn [24]
3 years ago
14

Please help i got no clue how to do dis

Chemistry
1 answer:
mamaluj [8]3 years ago
3 0

Answer:

Sulfur's Atomic #: 16

Fluorine's Atomic #: 9

Antimony's Atomic #: 51

Silver's Atomic #: 47

Rubidium's Atomic #: 37

Copper's Atomic #: 29

Tin's Atomic #: 50

Mercury's Atomic #: 80

Promethium's Atomic #: 61

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For the vaporization reaction Br2(l) → Br2(
oksian1 [2.3K]
    The  temperature  at   which  the  process  be   spontaneous  is  calculated  as  follows

delta  G  =  delta H  -T delta S

let  delta G  be =0

therefore  delta H- T  delta s =0

therefore  T=  delta  H/  delta  S
convert  31   Kj  to  J  =  31  x1000=  31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K


3 0
3 years ago
A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix
Alisiya [41]

Answer:

M_f=38.8\%

Explanation:

From the question we are told that:

Pressure P=747mmHg

Temperature T=298K

Volume V=11.1

Heat Produced Q=780kJ

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 n= (747/760) *11.1/ (0.0821*298)

 n=0.446mol

Therefore

 x+y=0.446

 x=0.446-y .....1

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

 x(889) + y(2220) = 760 ...... 2

Comparing Equation 1 and 2 and solving simultaneously

 x=0.446-y .....1

 x(889) + y(2220) = 760 ...... 2

 x=0.173

 y=0.273

Therefore

Mole fraction 0f Methane is mathematically given as

 M_f=\frac{x}{n}*100\%

 M_f=\frac{1.173}{0.446}*100\%

 M_f=38.8\%

7 0
3 years ago
5 The apparatus shown below was set up. Give explanations for the following observations.
lana [24]

Answer:

hope it helps brainliest pls

Explanation:

3 0
2 years ago
What is the net Ionic equation of HClO4(aq)+ NaOH(aq) = H2O(l)+ NaClO4(aq)
uranmaximum [27]
H^+(aq) + OH^-(aq) ---> H2O(l) 

<span>Na^+ and ClO4^- are the spectator ions.</span>
7 0
3 years ago
1. In the first step of the mechanism for this process, a phenoxide anion is generated. This phenoxide anion goes on to act as a
Tju [1.3M]

Answer:

See the explanation

Explanation:

In this case, in order to get an <u>elimination reaction</u> we need to have a <u>strong base</u>. In this case, the base is the phenoxide ion produced the phenol (see figure 1).  

Due to the resonance, we will have a more stable anion therefore we will have a less strong base because the negative charge is moving around the molecule (see figure 2).

Finally, the phenoxide will attack the <u>primary carbon</u> attached to the Cl. The C-Cl bond would be broken and the C-O would be produced <u>at the same time</u> to get a substitution (see figure 1).

3 0
3 years ago
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