Ask question

Ask question

All categories

3 years ago

14

An element X on reacting with oxygen forms an oxide X2O. this oxide dissolves in water and turns blue litmus red. a) Identify th

e element X and mention the nature of the compound formed. b) Write a balanced chemical equation for the above reaction

1 answer:

galben [10]3 years ago

4 0

Answer:

The unknown element is Carbon.

(a) X is Carbon, its oxide is of acidic nature

(b) C+ O2 → CO2

Explanation:

We are given an unknown element that reacts with oxygen.

X + O2 → XO2

It is given that the oxide XO2 turns blue litmus red which is shown by acids, so XO2 is an acidic oxide. Also X will be a Non metal because Non metallic oxide is Acidic in nature.

The Oxide XO2 is dissolving is water. The oxide upon reacting with water will give an Acid.

XO2 type of oxide is found in the 14th group of the periodic table generally

So we have options like C, Si and Ge as these only have the Acidic oxide.

But when it comes to reactivity with water Only Carbon satisfies the need so the unknown element X is C.

CO2 + H2O → H2CO3 which is an acid.

(a) Element X is Carbon (C), The nature of the compound formed is Acidic.

(b) The reaction given will be as follows

C+ O2 → CO2

Therefore the unknown element is Carbon.

You might be interested in

Gravity is best described as the attractive force___

Delvig [45]

Gravity is nest described as the attractive force that acts between any two objects on earth

Explanation:-

Gravity was found by Sir Eizak Newton
It has formula given by

$\\ \rm\Rrightarrow F=G\dfrac{Mm}{r^2}$

8 0

3 years ago

Read 2 more answers

The water in a pressure cooker boils at a temperature greater than 100°C because it is under pressure. At this higher temperatur

vazorg [7]

Answer:

the activation energy Ea = 179.176 kJ/mol

it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

Explanation:

From the given information

$T_1 = 100^0 C = 100+273 = 373 \ K \\ \\ T_2 = 113^0 C = 113 + 273 = 386 \ K$

$R_1 = \dfrac{1}{7}$

$R_2 = \dfrac{1}{49}$

Thus; $\dfrac{R_2}{R_1} = 7$

Because at 113.0°C; the rate is 7 time higher than at 100°C

Hence:

$In (7) = \dfrac{Ea}{8.314}( \dfrac{1}{373}- \dfrac{1}{386})$

1.9459 = $\dfrac{Ea}{8.314}* 9.0292 *10^{-5}$

$1.9459*8.314 = Ea * 9.0292*10^{-5}$

$16.1782126= Ea * 9.0292*10^{-5}$

$Ea = \dfrac{16.1782126}{ 9.0292*10^{-5}}$

Ea = 179.176 kJ/mol

Thus; the activation energy Ea = 179.176 kJ/mol

b)

here;

$T_2 = 386 \ K \\ \\T_1 = (89.8 + 273)K = 362.8 \ K$

$In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})$

$In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})$

$In (\dfrac{R_2}{R_1}) = 0.00357$

$\dfrac{R_2}{R_1}= e^{0.00357}$

$\dfrac{R_2}{R_1}= 1.0035$

where ;

$R_2 = \dfrac{1}7{}$

$R_1 = \dfrac{1}{t}$

Now;

$\dfrac{t}{7}= 1.0035$

t = 7.0245 mins

Therefore; it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

4 0

3 years ago

The only nonmetal in group 1

r-ruslan [8.4K]

Answer:

Hydrogen

Explanation:

Hydrogen is the only non metal in group on of the period table of elements.

3 0

3 years ago

As a forensic expert, Jane needs to handle many biological evidence samples simultaneously. What is the basic precaution that sh

madreJ [45]

Answer:

B. use a new pair of gloves for each piece of evidence

Explanation:

When it comes to the basic precautions of handling biological evidence samples, one has to prevent cross contamination. This refers to the<em> transfer of DNA from one evidence to another evidence</em>; thus, it is important for Jane to use a new pair of gloves for each piece of evidence in order to prevent such occurrence.

Wearing of gloves will also <em>prevent Jane's DNA from being implanted into the sample</em>, and it will keep her safe from contracting blood-borne pathogens like those in the saliva, blood or semen.

7 0

3 years ago

When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°

dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=8.30^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant =

m= molality = $\frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579$

$8.30^0C=1\times K_f\times 0.579$

$K_f=14.3^0C/m$

Let Mass of solute (KBr) = x g

$8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}$

$x=58.2g$

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

7 0

2 years ago