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RUDIKE [14]
3 years ago
8

In a rolling race, two objects are released from the top of two identical ramps. They then roll without slipping to the bottom o

f the ramp. If the two objects are 2 hoops of the same radius but different masses, which reaches the bottom first?
a. The lighter one reaches the bottom first
b. The heavier one reaches the bottom first
c. We don’t have enough information
d. They reach the bottom at the same time
Physics
2 answers:
Strike441 [17]3 years ago
7 0

Answer:

B

Explanation:

The answer is B the heavier item has more g force pushing it making it roll faster reaching the bottom of the ramp first.

mixer [17]3 years ago
6 0

Answer:

b. The heavier one reaches the bottom first.

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A poundal is the force required to accelerate a mass of 1 lbm at a rate of 1 ft/s2 , and a slug is the mass of an object that wi
ahrayia [7]

Answer:

We are given that

The

Mass of person = 135lbm

Weight of person on earth will be

= mass x gravity constant

= 135lbm x 32.174 ft/s2

=4343.49 lbm-ft/s2 x 1 poundal-s2/lbm-ft

= 4343.49 poundal

Again we are given that

Mass of person = 135 lbm

But here remember Mass remains the same

So

Weight of person on moon will be

mass x gravity constant on moon

= 135 lbm x 32.174 ft/s2 x 1/6

= 723.9 lbm-ft/s2 x 1 poundal-s2/lbm-ft

= 723.9poundal

But we know that

1 ft slug / lbf-s2 = 32.174 ft lbm/ lbf-s2

So

1 slug = 32.174 lbm

So then the Mass of person

= 135lbm x 1slug/32.174 lbm

=4.2slugs

So finally

Weight = 405 poundals is same as

405 lbm-ft/s2

So

Mass = 35 slug x 32.174 lbm/slug = 1126.09 lbm

Acceleration rate = weight /mass

= (405 lbm-ft/s2) / (1126.09 lbm)

= 0.3597ft/s2 x 0.305m/ft

= 1.179 m/s²

4 0
3 years ago
A block that has a mass M = 500 g is hanging at rest on a light string. A projectile with a mass m = 15 g moving horizontally wi
stira [4]

Answer:

2.8m

Explanation:

Convert to metric:

500g = 0.5 kg

15g = 0.015 kg

Assuming elastics collision, we could use the law of momentum conservation to calculate the speed of black and projectile post-collision V:

mv = (M + m)V

V = \frac{mv}{m+M} = \frac{0.015*255}{0.5 + 0.015} = 7.43 m/s

This would make the system moves up, which convert its kinetic energy to potential energy. By the law of energy conservation when the mass reaches its highest point (aka speed = 0)

E_k = E_p

0.5(M+m)V^2 = (M+m)gh

h = \frac{V^2}{2g} = \frac{7.43^2}{2*9.81} = 2.8m

8 0
4 years ago
If the distance between two charged objects increases, the electric force between them__
telo118 [61]

im probably wrong but probably increase because if they get closer the static/sparks to cause a reaction

8 0
3 years ago
A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wave
Ann [662]

Answer:

\lambda = 40 cm

Explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L = n \times \frac{1}{4} \lambda     ...............1

so

total length will be here

L = \frac{\lambda}{2} +  \frac{\lambda}{4}\\

L = \frac{3 \lambda }{4}

so \lambda  will be

\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}

\lambda = 40 cm

5 0
3 years ago
6th grade science I mark as brainliest.​
Viktor [21]

Answer:

divide 10 by 50.

Explanation:

Because its time over speed 10/50

7 0
3 years ago
Read 2 more answers
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