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Slav-nsk [51]
3 years ago
13

The phasor technique is not valid if the frequencies of the sinusoids in the time domain are different. Part F - Use phasors to

combine sinusoids The phasor technique makes it pretty easy to combine several sinusoidal functions into a single sinusoidal expression without using trigonometric identities. However, you cannot use the phasor technique in all cases. Select the expressions below for which the phasor technique cannot be used to combine the sinusoids into a single expression.
a. 45 sin(2500t – 50°) + 20 cos(1500t +20°)
b. 25 cos(50t + 160°) + 15 cos(50t +70°)
c. 100 cos(500t +40°) + 50 sin(500t – 120°) – 120 cos(500t + 60°) -100 sin(10,000t +90°) + 40 sin(10, 100t – 80°) + 80 cos(10,000t)
d. 75 cos(8t+40°) + 75 sin(8t+10°) – 75 cos(8t + 160°)
Engineering
2 answers:
AlladinOne [14]3 years ago
4 0

Answer:

  a, c

Explanation:

As the problem statement tells you, the phasor technique cannot be used when the frequencies are different. The frequencies are different when the coefficients of t are different. The different ones are highlighted.

a. 45 sin(2500t – 50°) + 20 cos(1500t +20°)

b. 25 cos(50t + 160°) + 15 cos(50t +70°)

c. 100 cos(500t +40°) + 50 sin(500t – 120°) – 120 cos(500t + 60°) -100 sin(10,000t +90°) + 40 sin(10, 100t – 80°) + 80 cos(10,000t)

d. 75 cos(8t+40°) + 75 sin(8t+10°) – 75 cos(8t + 160°)

guapka [62]3 years ago
4 0

Answer:

<h2>A and C</h2>

  • <em>By</em><em> </em><em>which</em><em> </em><em>the</em><em> </em><em>phaser</em><em> </em><em>technique</em><em> </em><em>cannot</em><em> </em><em>be</em><em> </em><em>used</em><em> </em><em>to</em><em> </em><em>combine</em><em> </em><em>the</em><em> </em><em>sinusoidal</em><em> </em><em>into</em><em> </em><em>a</em><em> </em><em>single</em><em> </em><em>expression</em><em>.</em>
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The chart shows the bids provided by four engineers to test a prototype.
klasskru [66]

Answer:

D

Explanation:

To know which is most or least cost-effective, it's not enough to look at only the per day rate, or only the time to complete.  You have to multiply them to get the total cost of the project.

\left[\begin{array}{ccccc}&Cost\ per\ day\ (\$)&Time\ to\ complete\ (days)&Total\ cost\ (\$)\\Zoe&500&8&4000\\Greg&650&10&6500\\Orion&400&12&4800\\Jin&700&5&3500\end{array}\right]

As you can see, Greg is the least cost-effective because he charges the most for the project.

8 0
3 years ago
What is the maximum thermal efficiency possible for a power cycle operating between 600P'c and 110°C? a). 47% b). 56% c). 63% d)
Anastasy [175]

Answer:

(b) 56%

Explanation:

the maximum thermal efficiency is possible only when power cycle is reversible in nature and when power cycle is reversible in nature the thermal efficiency depends on the temperature

here we have given T₁ (Higher temperature)= 600+273=873

lower temperature T₂=110+273=383

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=1-\frac{383}{873}

=1-0.43871

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5 0
2 years ago
A motor car shaft consists of a steel tube 30 mm internal diameter and 4 mm thick. The engine develops 10 kW at 2000 r.p.m. Find
tresset_1 [31]

The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.

<h3>What is power?</h3>

Power is the energy transferred per unit time.

Torque is find out by

P = 2πNT/60

10000 = 2π x 2000 x T / 60

T =47.74 N.m

The gear ratio Ne / Ns =4/1

Ns =2000/4 = 500

Ts =Ps x 60/(2π x 500)

Ts =190.96 N.m

Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))

τ max =T/J x D/2
where d₁ = 30mm = 0.03 m

           d₀ = 30 +(2x 4) = 38mm =0.038 m

Substitute the values into the equation, we get

τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)

τ max = 28.98 MPa.

Thus, the maximum shear stress in the tube is 28.98 MPa.

Learn more about power.

brainly.com/question/13385520

#SPJ1

7 0
2 years ago
For unrestrained cube made from linear, isotropic, homogeneous material the temperature increase causes strain in_____ direction
LenKa [72]

Answer: The answer is four; four

Explanation: This is because of the mixture of material used and the number of directions it causes strain I directly proportional to the number of times it causes stress.

7 0
3 years ago
True or False: Galvanized steel pipe can withstand moderate freezing.
yaroslaw [1]

Answer:

True

Explanation:

Older galvanized steel pipes, which have a tendency to freeze, are a bit more forgiving and will likely not burst. They can withstand extreme cold and warm temperatures.

5 0
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