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3 years ago

What is a geochemist

1 answer:

3 0

An expert in or student of the branch of science concerning the chemical composition of the earth and its rocks and minerals.

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A solution with a hydrogen ion concentration of 3.25 × 10-2 m is ________ and has a hydroxide concentration of _______

Romashka-Z-Leto [24]

To know the acidity of a solution, we calculate the pH value. The formula for pH is given as:

pH = - log [H+] where H+ must be in Molar

We are given that H+ = 3.25 × 10-2 M

Therefore the pH is:

pH = - log [3.25 × 10-2]

pH = 1.488

Since pH is way below 7, therefore the solution is acidic.

To find for the OH- concentration, we must remember that the product of H+ and OH- is equivalent to 10^-14. Therefore,

[H+]*[OH-] = 10^-14 
[OH-] = 10^-14 / [H+]

[OH-] = 10^-14 / 3.25 × 10-2

[OH-] = 3.08 × 10-13 M

Answers:

Acidic

[OH-] = 3.08 × 10-13 M

6 0

3 years ago

Give the name of the prefix and the quantity indicated by the following symbols that are used with SI base units.

Serhud [2]

Answer:

A. Centi, 10*-2

B. Deci, 0.1 or 10*-1

C. Giga, 10*9

D. Kilo, 10*3

E. Milli, 10*-3

F. Nano, 10*-9

G. Pico, 10*-12

H. Tera, 10*12

7 0

3 years ago

Someone answer the limited regent...

OleMash [197]

Answer:

20 g Ag

General Formulas and Concepts:

Chemistry - Stoichiometry

Using Dimensional Analysis

Chemistry - Atomic Structure

Reading a Periodic Table

Explanation:

Step 1: Define

[RxN] Cu (s) + AgNO₃ (aq) → CuNO₃ (aq) + Ag (s)

[Given] 10 g Cu

Step 2: Identify Conversions

[RxN] 1 mol Cu = 1 mol Ag

Molar Mass of Cu - 63.55 g/mol

Molar Mass of Ag - 197.87 g/mol

Step 3: Stoichiometry

$10 \ g \ Cu(\frac{1 \ mol \ Cu}{63.55 \ g \ Cu})(\frac{1 \ mol \ Ag}{1 \ mol \ Cu} )(\frac{197.87 \ g \ Ag}{1 \ mol \ Ag} )$ = 16.974 g Ag

Step 4: Check

We are given 1 sig fig. Follow sig fig rules and round.

16.974 g Ag ≈ 20 g Ag

6 0

3 years ago

6) A volume of 473 mL of oxygen was collected at 27°C. What volume would the oxygen occupy at

sertanlavr [38]

Answer : The volume of oxygen occupy at 173° would be, 703.2 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=473mL\\T_1=27^oC=(27+273)K=300K\\V_2=?\\T_2=173^oC=(173+273)K=446K$

Now put all the given values in above equation, we get:

$\frac{473mL}{300K}=\frac{V_2}{446K}\\\\V_2=703.2mL$

Therefore, the volume of oxygen occupy at 173° would be, 703.2 mL

6 0

3 years ago

True or false, The four units that must always be used when using the ideal gas are 44.0 liters

Bogdan [553]

Answer:

for volume only liters can be used

Explanation:

4 0

3 years ago