<u>Answer:</u> The activation energy of the reaction is 124.6 kJ/mol
<u>Explanation:</u>
To calculate activation energy of the reaction, we use Arrhenius equation, which is:
where,
= equilibrium constant at 79°C =
= equilibrium constant at 26°C =
= Activation energy of the reaction = ?
R = Gas constant = 8.314 J/mol K
= initial temperature =
= final temperature =
Putting values in above equation, we get:
Hence, the activation energy of the reaction is 124.6 kJ/mol
Please, find the complete question in the picture attached.
Answer:
1. Na₂O
2. AlF₃
3. MgO
4. Ca₃P₂
Explanation:
1. Na⁺ and O²⁻
An ionic compound will be formed when two ions of opposite charge attract each other.
The positive ion is called cation and the negative ion is called anion.
Thus, every ionic compound has a cation and an anion electrostatically bonded.
The ions must combine in a proportion that genders a neutral compound: so you must have as many cations as negative charge has one anion and as many anions as positive charge has one cation.
This is, if the cation has charge +x, there will be x anions, and if the anion has charge -y, there will be y cations.
Simbolically:
As you see, the subscripts for each element in the chemical formula are obtained by the exchage of the charges of the ions.
Then, for Na⁺ and O²⁻, the subscript for Na will be 2 and the subscript for O will be 1; and the formula of the ionic compound formed by this pair ot ions is:
2. Al³⁺ and F⁻
Thus the ionic compound formed by this pair of ions is:
3. Mg²⁺ and S²⁻
That results in the formula: Mg₂S₂
Except for some special compounds, the chemical formula is simplified, dividing by the least common denominator. In this case, that means that the two 2 subscripts are simplified to 1, and the final chemical formula for the ionic compound formed by this pair of ions is:
4. Ca²⁺ and P³⁻
Hence, the ionic compound formed by these two ions is:
