Answer:
I=1A
Explanation:
In parallel combination voltage is same
In R1
V=IR
V=2×4
V=8V
In R2
V=IR
I=V/R
I=8/8
I=1A
We use the binomial theorem to answer this question. Suppose we have a trinomial (a + b)ⁿ, we can determine any term to be:
[n!/(n-r)!r!] a^(r) b^(n-r)
a.) For x⁵y³, the variables are: x=a and y=b. We already know the exponents of the variables. So, we equate this with the form of the binomial theorem.
r = 5
n - r = 3
Solving for n,
n = 3 + 5 = 8
Therefore, the coefficient is equal to:
Coefficient = n!/(n-r)!r! = 8!/(8-5)!8! = 56
b.) For x³y⁵, the variables are: x=a and y=b. We already know the exponents of the variables. So, we equate this with the form of the binomial theorem.
r = 3
n - r = 5
Solving for n,
n = 5 + 3 = 8
Therefore, the coefficient is equal to:
Coefficient = n!/(n-r)!r! = 8!/(8-3)!8! = 56
If we neglet air resistance for both objects then both will fall parallely(at same time) because time taken by both objects is independent of mass. there is famous experiment i.e"feather coin experiment" . normally we think that heaver objects falls faster but this is wrong concept. it depends on medium in which objects are moving.
thanku
To solve this problem it is necessary to apply the concepts related to the condition of path difference for destructive interference between the two reflected waves from the top and bottom of a surface.
Mathematically this expression can be described under the equation
Where
n = Refractive index
t = Thickness
In terms of the wavelength the path difference of the reflected waves can be described as
Where
\lambda = Wavelenght
Equation the two equations we have that
Our values are given as
Wavelength of light
Therefore the minimum thickness of the oil for destructive interference to occur is approximately 34.0 nm
Answer:
0.81452 atm
Explanation:
= Initial pressure = 1.43 L
= Volume
= Initial temperature = (28+273.15) K
= Final temperature = (-35+273.15) K
= Final pressure
From the ideal gas law we have
The pressure in the cylinder is 0.81452 atm
