Answer:
metano= CH4
C= 12 g/mol
H= 1g/mol x 4 = 4g/mol
CH4= 12g/mol + 4g/mol = 16g/mol
(las masas están aproximadas).
The answer is l did 16+2 =18
First, we use avogadro's number to convert atoms into moles. Then, relate the number of moles from elemental to the compound. Lastly, we use conditions at STP to calculate the volume. We do as follows:
<span>9.86 x 10²⁸ O-atoms ( 1 mol / 6.022x10^23 atoms O) ( 1 mol N2O2 / 2 mol O ) ( 22.4 L / 1 mol ) = 1833809.37 L needed</span>