What happens to an object when you halve the mass? Hurry please !

vampirchik [111]

Thermodynamics is the branch of physical science which deals with the relationship between heat and other forms of energy like chemical energy, mechanical or electrical. Here are examples of thermodynamics that are commonly seen in everyday living: When you accidentally wrecked or bumped your car, you came out alive and just slightly hurt, because it was the car that that absorbed the energy of the impact. Another example is that, during cooking. When you are cooking, the heat is being transferred to the pan and then to the food that you are cooking.

5 0

4 years ago

Two long, parallel wires are attracted to each other by a force per unit length of 305 µN/m. One wire carries a current of 25.0

kykrilka [37]

To solve this problem we will use the concepts related to the electromagnetic force related to the bases founded by Coulumb, the mathematical expression is the following as a function of force per unit area:

$\frac{F}{L} = \frac{kl_1l_2}{d}$

Here,

F = Force

L = Length

k = Coulomb constant

I =Each current

d = Distance

Force of the wire one which is located along the line y to 0.47m is $305*10^{-6}N/m$ then we have

$l_2 = \frac{F}{L} (\frac{d}{kl_1})$

$l_2 = (305*10^{-6}N/m)(\frac{0.470m}{(2*10^{-7})(25A))})$

$l_2 = 28.67A$

Considering the B is zero at

$y = y_1$

$\frac{kI_2}{2\pi y} =\frac{kI_1}{2\pi y_1}$

$\frac{(4\pi*10^{-7})(28.67)}{2\pi (y_1)} = \frac{(4\pi *10^{-7})(25)}{2\pi (0.47-y_1)}$

$y_1 = 0.25m$

Therefore the value of y for the line in the plane of the two wires along which the total B is zero is 0.25m

5 0

4 years ago

A train starts from a station with a constant acceleration of at = 0.40 m/s2. A passenger arrives at the track time t = 6.0s aft

jok3333 [9.3K]

Answer:

4.8 m/s

Explanation:

When she catches the train,

They will have travelled the same distance.and
Their speeds will be equal

The formula for the distance covered by the train is

d = ½at² = ½ × 0.40t² = 0.20t²

The passenger starts running at a constant speed 6 s later, so her formula is

d = v(t - 6.0)

The passenger and the train will have covered the same distance when she has caught it, so

(1) 0.20t² = v(t - 6.0)

The speed of the train is

v = at = 0.40t

The speed of the passenger is v.

(2) 0.40t = v

Substitute (2) into (1)

0.20t² = 0.40t(t - 6.0) = 0.40t² - 2.4 t

Subtract 0.20t² from each side

0.20t² - 2.4t = 0

Factor the quadratic

t(0.20t - 2.4) = 0

Apply the zero-product rule

t =0 0.20t - 2.4 = 0

0.20t = 2.4

(3) t = 12

We reject t = 0 s.

Substitute (3) into (2)

0.40 × 12 = v

v = 4.8 m/s

The slowest constant speed at which she can run and catch the train is 4.8 m/s.

A plot of distance vs time shows that she will catch the train 6 s after starting. Both she and the train will have travelled 28.8 m. Her average speed is 28.8 m/6 s = 4.8 m/s.