Question

What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor

Answer 1

Complete Question

A 8.0 A current is charging a 1.0 -cm-diameter parallel-plate capacitor. What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor?

Answer:

The magnetic field is  $B = 6.4*10^{-4} \ T$

Explanation:

From the question we are told that

    The current is  $I = 8.0 \ A$

    The diameter is  $d = \ cm = \frac{1}{100} = 0.01 m$

      The position considered is  $d = 2.5 \ mm = 0.0025 \ m$

 Generally the magnetic field is mathematically represented as

           $B = \frac{\mu_o * I }{ 2 \pi d}$

Here $\mu_o$ is permeability of free space with value  

$\mu_o = 4\pi * 10^{-7} \ N/A^2$

      So

                 $B = \frac{ 4\pi * 10^{-7} * 8 }{ 2 \pi * 0.0025 }$

=>               $B = \frac{ 2 * 10^{-7} * 8 }{ * 0.0025 }$

=>               $B = 6.4*10^{-4} \ T$