Question

What is the period of an object that makes 6 revolutions a minute?

Answer 1

Answer:

T = 10 s

Explanation:

First, we need to find the frequency of the object as follows:

$Frequency = f = \frac{Speed\ in\ rpm}{60}$

where,

Speed = Angular Speed = 6 rpm

Therefore,

$f = \frac{6\ rpm}{60}\\\\f = 0.1\ Hz$

Now, for time period (T):

$Time\ Period = T = \frac{1}{f}\\\\T = \frac{1}{0.1\ Hz}$

T = 10 s