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SSSSS [86.1K]
3 years ago
10

Which Circut Model is more efficient, why?

Physics
1 answer:
vovangra [49]3 years ago
7 0

Answer:

right one is more efficient

Explanation:

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A planet has a period of revolution about the Sun equal to and a mean distance from the Sun equal to R .T^2 varies directly as _
shutvik [7]

T² caries directly as R³ .

This is Kepler's 3rd law of planetary motion .
4 0
3 years ago
Can anyone tell me which ones of these are true and which ones are false pls
Akimi4 [234]

There are two important facts to recall that will help answer this question:

1. The resistance of a segment of conducting wire is given by this equation:

R = ρL/A

ρ is the resistivity of the material making up the wire. This value is a constant that depends on the properties of the material. Resistivities for various materials can be found with a quick Google search.

L is the length of the wire.

A is the cross-sectional area of the wire.

From this equation you can tell that a wire's resistance will increase if it is made longer and/or thinner, and the resistance will decrease if it is made shorter and/or thicker. Mathematically speaking, the resistance is directly proportional to the length and inversely proportional to the cross-sectional area.

2. The other fact is that a conductor's resistance is also dependent on its temperature. Generally, as a conductor gets hotter, its resistance increases.


Let us now tackle the list of statements:

1. A shorter wire will allow electricity to move through at a higher rate than a longer wire.

According to the equation for a conductor's resistance, a shorter wire will have a smaller resistance.

Now recall that current is the movement of electric charges and Ohm's law:

V = IR

V is the applied potential difference between the ends of the wire.

I is the current.

R is the resistance.

Assuming you keep the potential difference constant, when you have a smaller resistance, you will have a larger current.

Statement 1 is correct.


2. A short, thick, cold wire is the best conductor.

According to the equation for a conductor's resistance, a shorter, thicker wire will have lesser resistance. A cold temperature will also help to keep the resistance low. A low resistance means a higher current.

Statement 2 is correct.


3. How well a material conducts current is an internal factor affecting resistance.

Statement 3 is correct, assuming the physical property in question is the material's resistivity. The resistivity is one of the factors in the equation for a conductor's resistance.

4. If you double the length of a wire, you cut the resistance in half.

According to the equation for a conductor's resistance, increasing the length of a wire increases the resistance. Statement 4 is false.


5. If you double the thickness of a wire, you cut the resistance in half.

According to the equation for a conductor's resistance, increasing the thickness of a wire decreases its resistance. Statement 5 is true.


6. Superconductors have no measurable resistance.

A superconductor by definition is able to conductor electric current with virtually no resistance. Statement 6 is true.


7. The higher the temperature of the conductor, the lower the resistance.

A conductor's resistance generally increases with temperature. Statement 7 is false.


8. The resistance in a wire with less thickness is less.

According to the equation for a conductor's resistance, making a wire thinner will increase its resistance. Statement 8 is false.


9. Thickness, length, and temperature are internal factors that affect resistance.

Thickness (cross-sectional area) and length are both factors in the equation determining a conductor's resistance. Temperature is also known as a factor that affects resistance. Statement 9 is true.


10. When a light is first switched on, the light bulb's filament has a lower resistance than after it gives off light for awhile.

A device that draws a current will generally heat up given sufficient time. This increases the device's resistance. Statement 10 is correct.

4 0
4 years ago
Read 2 more answers
13. A transformer has a primary coil with 600 turns and a secondary coil with 300 turns. If the output voltage is 320 volts, wha
vivado [14]
His is a step down transformer since n(primary) is greater than n(seconcary). You relate the input voltage with the ouput voltage with the following equation: 

<span>Vout = n2/n1*Vin (n2/n1 is essentially your 'transfer function' that dictates what a specified input would produce) </span>

<span>Solving the equation: </span>

<span>Vin = Vout*n1/n2 = (320V)*(600/300) = 640 V </span>

<span>This is checked by seeing if Vin is greater than Vout, which it is for a step down transformer.</span>
5 0
3 years ago
The chart shows data for a moving object.
Brut [27]
The object is not accelerating
8 0
3 years ago
Calculate the temperature increase in a 1.00-kg sample of water that results from the conversion of gravitational potential ener
Llana [10]

To solve this problem it is necessary to apply the concepts concerning the conservation of both potential and thermodynamic energy of the body. That is to say that as the body has a loss of potential energy it is gained in the form of thermal energy on water. If the potential energy is defined as

PE = mgh

Where,

m= mass

g = Gravitational acceleration

h = Height

And thermal energy is obtained as

Q = mC_p\Delta T

Where,

\Delta T = Change in Temperature

C_p = Specific Heat

m = Mass

We can equate this equation and rearrange to find the change at the Temperature, then

mgh = mC_p\Delta T

\Delta T = \frac{gh}{C_p}

Our values are given as,

C_p = 4186J/Kg\cdot K \rightarrow Specific Heat Water

Using energy conservation

g = 9.8m/s^2

h = 807m

Replacing,

\Delta T = \frac{(9.8)(807)}{4186}

\Delta T = 1.89K

Therefore the temperature increase in a 1kg sample of water is 1.89K

8 0
3 years ago
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