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tangare [24]
3 years ago
10

NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts. The sup

ply storage area of the lunar outpost, where gravity is 1.63 m/s2, can only support 1 x 10^5 N.
Physics
1 answer:
Finger [1]3 years ago
3 0

Complete question :

NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts. The supply storage area of the lunar outpost, where gravity is 1.63 m/s2, can only support 1 x 10^5 N. What is the maximum WEIGHT of supplies, as measured on EARTH, NASA should plan on sending to the lunar outpost

Answer:

601,220N

Explanation:

Given that:

Gravity at lunar outpost = 1.63m/s²

Acceleration due to gravity on earth = 9.8m/s²

Supported weight = 1 * 10^5 N

Maximum weight of supplies as measured on earth;

(Ratio of the gravities) * weight of supplies

(9.8m/s² / 1.63m/s²) * (1 * 10^5 N)

6.0122 * (1 * 10^5)

6.0122 * 10^5 N

= 601,220 N

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A tire swing hanging from a branch reaches nearly to the ground. How could you estimate the height of the branch using only a st
blagie [28]

Answer:

A stop watch measures time and the number of seconds making an osculation is the period T

Which is T = 2π√(L/g)........solving for L (the length of the pendulum),

Then the L = T²x g/( 4πr²) substitute and then u find length or height of the swing

4 0
3 years ago
How long does it take a car travelling at 80 m/s to decelerate to 18 m/s with an acceleration rate of -16m/s?
sertanlavr [38]
  • initial velocity=u=80m/s
  • Final velocity=v=18m/s
  • Acceleration=a=-16m/s^2
  • Time=t

We know

\boxed{\sf a=\dfrac{v-u}{t}}

\\ \sf\longmapsto t=\dfrac{v-u}{a}

\\ \sf\longmapsto t=\dfrac{18-80}{-16}

\\ \sf\longmapsto t=\dfrac{-62}{16}

\\ \sf\longmapsto t=3.8s

4 0
3 years ago
*Urgent* I WILL GIVE BRAINLIEST
Butoxors [25]

Answer:

walking to school

Explanation:

Driving a car to school

, and taking the bus to school​ both take up energy, unlike walking to school.

unless ur talking about energy, counting energy you produce and use to complete things, then it would be the 3rd one, taking the bus to school.

4 0
3 years ago
The amount of work done by two boys who apply 200 N of force in an
Aleksandr [31]

The amount of work done by two boys who apply 200 N of force in an unsuccessful attempt to move a stalled car is 0.

Answer: Option B

<u>Explanation: </u>

Work done is the measure of work done by someone to push an object from its present position. We can also define work done as the amount of forces needed to move an object from its present position to another position. So the amount of work done is directly proportionate to the product of forces acting on the object and the displacement of the object.  

           \text { Work done }=\text { Force } \times \text { displacement }

So in this present case, as the two boys have done an unsuccessful attempts to push a stalled car so that means the displacement of the car is zero as there is no change in the position of the car. But they have applied a force of 200 N each. So the amount of work done will be

           \text { Work done }=200 \mathrm{N} \times 0=0

Thus, the amount of work done by two boys will be zero due to their unsuccessful attempt to move a stalled car.

8 0
3 years ago
A car goes from rest to a velocity of 108 km/h north in 10s what is the car's acceleration in m/s2
fomenos

initial velocity of the car given as

v_i = 0

final velocity is given as

v_f = 108 km/h

as we know that

1 km/h = 0.277 m/s

now we can convert final speed into m/s

v_f = 108 * 0.277 = 30 m/s

now acceleration is rate of change in velocity

a = \frac{v_f - v_i}{t}

a = \frac{30 - 0}{10}

a = 3 m/s^2

so the acceleration of the car is 3 m/s^2

7 0
3 years ago
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