Answer:
The maximum height obtained by the object is approximately 31.855 m
Explanation:
The vertical velocity of the object = 25.0 m/s
The height reached by the object, is given by the following formula;
v² = u² - 2 × g × h
Where;
u = The initial velocity of the object = 25.0 m/s
v = The final speed of the object = 0 m/s at maximum height
h = The maximum height obtained by the object
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values, gives;
0² = (25.0 m/s)² - 2 × 9.81 m/s² × h
2 × 9.81 m/s² × h = (25.0 m/s)²
h = (25.0 m/s)²/(2 × 9.81 m/s²) ≈ 31.855 m
The maximum height obtained by the object, h ≈ 31.855 m.
Answer:
Hence the order of the bright fringe is 7.
Explanation:
Diffraction can be defined as the deviation from rectilinear propagation and diffraction grating is used to measuring the wavelength of light using a spectrometer.
We have the formula d sin∅ = n l
We have to find the value of n in this equation and all other values are given.
Here d = 55000 lines
∅ = 12.23°
Wavelength , l = 550 nanometer
n is the order of the bright line.
Substitute these values in the given equation,
55000 sin(12.23°) = n
n = 7
Hence the order of the bright fringe is 7.
The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s is 107 s
<h3>Data obtained from the question</h3>
The following data were obtained from the question given above:
- Initial velocity (u) = 11.1 Km/s
- Final velocity (v) = 11.7 Km/s
- Distance (s) = 1220 Km
- Time (t) =?
<h3>How to determine the time</h3>
The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s can be obtained as illustrated below:
s = (u + v)t / 2
Cross multiply
(u + v)t = 2s
Divide both sides by (u + v)
t = 2s / (u + v)t
t = (2 × 1220) / (11.1 + 11.7)
t = 2440 / 22.8
t = 107 s
Thus, the time taken for the spaceship to change its speed is 107 s
Learn more about speed:
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