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3 years ago

A) It is very dry at the equator because it is so hot.

Physics

1 answer:

bixtya [17]3 years ago

6 0

A) It is very dry at the equator because it is so hot.

False. It depends on what else is around.

The Sahara Desert is near the Equator.

But so is the Amazon rain forest.

B) Higher places are usually warmer because they are closer to the Sun.

False. Higher places are usually colder, because the air is thinner.

C) Land masses change the direction of currents.

True

D)The sun provides energy needed for the evaporation process. Gravity allows water droplets to fall as precipitation.

True

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What is the advantage of designing a thermos so that it has a vacuum layer surrounding the area where hot liquids are started??

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The sun's radiation has different wavelengths. the shorter is the radiation's wavelength, the weaker is the radiation's energy.

NeX [460]

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3 years ago

A mass with mass 4 is attached to a spring with spring constant 24 and a dashpot giving a damping 20. The mass is set in motion

aleksandrvk [35]

Answer: $x(t) = 14e^{-2t} - 10e^{-3t}$

Explanation: In a mass-spring-damper system, the differential equation that rules the motion of the mass is: mx" + cx' + kx = 0

Using m = 4, k = 24 and c = 20, we have

4x" + 20x' + 24x = 0

Simplifying, we have

x" + 5x'+ 6x = 0

The characteristic equation of this differential is

$r^{2} + 5r + 6 = 0$

The solutions for the quadratic equation are: $r_{1} = -2$ and $r_{2} = -3$

Hence:

x(t) = $C_{1}e^{-2t} + C_{2}e^{-3t}$

x'(t) = $-2C_{1}E^{-2t} - 3C_{2}e^{-3t}$

To determine the constants, we have the initial conditions x(0) = 4 and

x'(0) = 2, then:

$x(0) = C_{1} + C_{2} = 4\\ C_{1} = 4 - C_{2}$

$x'(0) = -2C_{1} -3C_{2} = 2\\-2(4-C_{2}) -3C_{2} = 2\\C_{2} = -10\\C_{1} = 4 - C_{2}\\C_{1} = 14$

Substituing the constants:

$x(t) = 14e^{-2t} - 10e^{-3t}$

The position function for this system is: $x(t) = 14e^{-2t} - 10e^{-3t}$

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3 years ago

A very long, straight wire has charge per unit length 3.20 x 10^-10 c>m. At what distance from the wire is the electric-field

vovangra [49]

at 2.304×10⁹m the electric field magnitude equal to 2.50 nc.

electric field due to a long uniformly charged wire is given as,

E= 2kλ/r

where,

k is a constant

λ is uniform charge density

r is the distance from the wire

λ = 3.20 × 10⁻¹⁰C/m

k= 9×10⁹

therefore r = 2kλ/E

on substituting value we get,

r= 2.304×10⁹m

learn more about electric field due to a uniformly charged wire here:

brainly.com/question/28166144

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2 years ago

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