Answer:
speed=5cm/minute
Explanation:
Given at 2:00PM the hermit is at 10cm mark
Also given that the hermit reaches 60cm mark at 2:10PM
Therefore the time elapsed is 10 minutes =
the distance travelled by the hermit is 60-10=50cm=0.5m
We know that
speed = m/sec=5cm/minute
The energy range expected is 6.6 × 10^-19 J < E < 7.33 × 10^-19 J
The energy of the photon is given by;
E = hc/λ
E = energy of the photon
h = Plank's constant
c = speed of light
λ = wavelength of light
For the upper boundary range;
E = ?
h = 6.6 × 10^-34 Js
c = 3 × 10^8 m/s
λ = 270 × 10^-9
E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 270 × 10^-9
E = 7.33 × 10^-19 J
For the lower range;
E = ?
h = 6.6 × 10^-34 Js
c = 3 × 10^8 m/s
λ =300 × 10^-9
E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 300 × 10^-9
E = 6.6 × 10^-19 J
Hence, the energy range 6.6 × 10^-19 J < E < 7.33 × 10^-19 J
Learn more: brainly.com/question/24857760
Answer:
Density should be 8.5
Explanation:
When you subtract 17.2-10.0 for water displacement you get 7.2 which is the volume and you divide it by 15.7 so your equation will be 15.7/7.2 = 8.5
m = mass of the truck traveling = 2500 kg
v = speed of the truck traveling = 75 km/h = 75 (km/h) (1000 m/ 1 km) (1 h /3600 sec) = 20.83 m/s
h = plank's constant = 6.63 x 10⁻³⁴
λ = wavelength of truck = ?
according to de broglie's principle, wavelength of truck is given as
λ = h/(mv)
inserting the values in the above equation
λ = (6.63 x 10⁻³⁴)/((2500) (20.83))
λ = 1.3 x 10⁻³⁸ m