The amount of KNO₃ precipitated out of solution when you cooled the solution from 100°C to -22°C is obtained from the solubility curve
<h3>What is a solubility curve?</h3>
A solubility curve is a curve of the solubility of a solute against temperature.
The solubility curve shows that the solubility of different solute at different temperatures.
The solubility curve of KNO₃ is as shown. Solubility at 100 °C and -22 °C is not shown in the curve.
However, the amount of KNO₃ precipitated out of solution when cooled the solution from 100 °C to -22 °C can be determined by subtracting the amount of solute dissolve at -22 °C from that dissolved at 100 °C.
In conclusion, the solubility curve is used to determined the amount of solute dissolved in a given volume of solvent at different temperatures.
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Answer:
True
Explanation:
A disaccharide is a sugar and the general molecular formula of a disaccharide is C₁₂H₂₂O₁₁.
A disaccharide is formed when two monosachharide units are joined by a covalent bond called the glycosidic bond.
The glycosidic bond in a disaccharide is formed by dehydration reaction between the two monosachharide units. The removal of the water molecule results in the formation of the glycosidic linkage.
For example: maltose a disaccharide, is formed when two molecules of glucose are joined by a (1→4) glycosidic bond. As, the glycosidic bond is formed between the carbon 1 of one glucose unit and carbon 4 of another glucose unit.
Therefore, in a disaccharide the two monosaccharide units are joined by a glycosidic bond or linkage.
Therefore, the given statement is TRUE.
Answer:its D.
Explanation:
Energy is transformed first from chemical energy to electrical energy and then from electrical energy to light and heat energy.
Alright sorry you're getting the answer hours later, but i can help with this.
so you're looking for specific heat, the equation for it is <span>macaΔTa = - mbcbΔTb with object a and object b. that's mass of a times specific heat of a times final minus initial temperature of a equals -(mass of b times specific heat of b times final minus initial temperature of b)
</span>so putting in your values is, 755g * ca * (75 celsius - 84.5 celsius) = -(50g * cb * (75 celsius - 5 celsius))
well we know the specific heat of water is always 4180J/kg celsius, so put that in for cb
with a bit of simplification to the equation by doing everything on each side first you have, -7172.5 * ca = -14630000
divide both sides by -7172.5 so you can single out ca and you get, ca= 2039.74
add units for specific heat which are J/kg celsius and the specific heat of the material is 2039.74 J/kg celsius
Answer: a + 2
Explanation: Alkali Earths or Group II has an ionization charge of a + 2. Alkali Metals have a ionization a + 1. Halogens or cold elements have a ionization of a +3.