The sun is more massive than Earth,so

2 answers:

8 0

A and c are correct I think, because as the sun is so hot anyone wanting to test it would die. Google it to double check ❤ good luck with whatever you're doing

zhuklara [117]3 years ago

8 0

C is the correct answer to your question

You might be interested in

In an experiment to measure the acceleration due to gravity, g two values, 9.96 m/s2 and 9.72 m/s2 , are determined. Find (1) th

alexira [117]

Answer:

(1) Percent Difference = 2.47%

(2) Percent Error (9.96 m/s²) = 1.63 %

Percent Error (9.72 m/s²) = 0.82 %

(3) Percent Error (Mean) = 0.41 %

Explanation:

(1)

Percent Difference = [(9.96 m/s² - 9.72 m/s²)/(9.72 m/s²)]*100 %

Percent Difference = 2.47%

(2)

Percent Error = (|Measured Value - Original Value|/Original Value)*100%

Therefore,

Percent Error (9.96 m/s²) = (|9.96 m/s² - 9.8 m/s²|/9.8 m/s²)*100%

Percent Error (9.96 m/s²) = 1.63 %

Now,

Percent Error (9.72 m/s²) = (|9.72 m/s² - 9.8 m/s²|/9.8 m/s²)*100%

Percent Error (9.72 m/s²) = 0.82 %

(3)

First we need to find the mean of values:

Mean = (9.96 m/s² + 9.72 m/s²)/2

Mean = 9.84 m/s²

Therefore,

Percent Error (Mean) = (|9.84 m/s² - 9.8 m/s²|/9.8 m/s²)*100%

Percent Error (Mean) = 0.41 %

8 0

3 years ago

All of the following activities produce quantitative data exept

Keith_Richards [23]

Answer:

The answer to your question are A and C

Explanation:

Quantitative data are quantities, something that we get after measuring something.

A. Measuring the rate of gas production from a chemical. This example is a quantitative measure, because we are measuring the rate.

B. Describing the clarity of water in a sample If we are describing something, means that we are not measuring anything, so this is not a quantitative measure.

C. Calculating the energy released from an electrochemical reaction If we are not measuring but we are using the data somebody else got to calculate energy, them this is a quantitative data.

7 0

3 years ago

From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of

alexandr1967 [171]

Answer:

The value is $h = 11930 \ m$