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3 years ago

Once a metamorphic rock, always a metamorphic rock. Rocks cannot change from one type of a rock to another.

Physics

1 answer:

Gennadij [26K]3 years ago

5 0

Answer:

False

Explanation:

Metamorphic rock can melt into magma or weathers down (erosion) into sediments.

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A 120.0 kg crate is placed on a 15.00°

Citrus2011 [14]

F = 2820.1 N

Explanation:

Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as

Fnet = ma = 0 (a = 0 no sliding)

= F - mgsin15°

= 0

F = mgsin15°

= (120 kg)(9.8 m/s^2)sin15°

= 2820.1 N

7 0

3 years ago

Type the correct answer in each box. Round your answers to the nearest hundredth.

sergey [27]

Hi there!

$\large\boxed{PE = 7.35 J, \text{ }v \approx 3.13 m/s}$

To find the potential energy of the ball at B, we can use the equation:

PE = mgh

Plug the given gravity, mass, and height:

PE = (1.5)(0.5)(9.8) = 7.35 J

At A, all of this potential energy is changed to kinetic energy, so we can use the following equation:

v = √2KE/m

Plug in the solved for energy and mass:

v = √2(7.35)/1.5

Solve:

v ≈ 3.13 m/s

7 0

3 years ago

Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia

melisa1 [442]

Answer:

$H_2 = 91.55 km$

Explanation:

Gravity on the surface of planet is given as

$g = \frac{GM}{R^2}$

as we know that

$M = 8.93 \times 10^{22} kg$

$R = 1821 km$

now gravity on the planet is

$g = \frac{(6.67 \times 10^{-11})(8.93 \times 10^{22})}{(1821 \times 10^3)^}$

so we have

$g = 1.8 m/s^2$

now we know that

$H_{max} = \frac{v^2}{2g}$

so we will say

$\frac{H_1}{H_2} = \frac{g_2}{g_1}$

$\frac{500}{H_2} = \frac{9.81}{1.8}$

$H_2 = 91.55 km$

5 0

3 years ago

Water has a specific heat capacity nearly nine times that of iron. Suppose a 50-g pellet of iron at a temperature of 200∘C is dr

miv72 [106K]

Answer:

a. closer to 20∘C

Explanation:

$m_{p}$ = mass of pallet = 50 g = 0.050 kg

$c_{p}$ = specific heat of pallet = specific heat of iron

$T_{pi}$ = Initial temperature of pellet = 200 C

$m_{w}$ = mass of water = 50 g = 0.050 kg

$c_{w}$ = specific heat of water

$T_{wi}$ = Initial temperature of water = 20 C

$T_{e}$ = Final equilibrium temperature

Also given that

$c_{w} = 9 c_{p}$

Using conservation of energy

Energy gained by water = Energy lost by pellet

$m_{w} c_{w} (T_{e} - T_{wi}) = m_{p} c_{p} (T_{pi} - T_{e})\\(0.050) (9) c_{p} (T_{e} - 20) = (0.050) c_{p} (200 - T_{e})\\ (9) (T_{e} - 20) = (200 - T_{e})\\T_{e} = 38 C$

hence the correct choice is

a. closer to 20∘C

4 0

4 years ago

5) Find the length of guitar string that would vibrate at a fundamental frequency of 825 Hz if the string is stretched so that t

Mariulka [41]

Áp dụng công thức tính độ dài ạ

6 0

2 years ago